Explanation Given: Decibel reading of one sound is 5. Another sound has a decibel of 7. Approach: Decibel is a unit of Loudness of sound. The number of decibels is 10 times the logarithms of the relative intensity. decibels = 10 log ( relative intensity ) … ( 1 ) Calculation: Calculate the difference in decibel level. difference = 7 − 5 = 2 Let the relative intensity be x . The difference between the decibel level is 2, so the difference in logarithms is 2 10 = 0

6th Edition

ISBN: 9780357422496

Author: Crauder

Publisher: CENGAGE L

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Chapter 4.5, Problem 9SBE

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The way in which the relative intensities of two sounds compare.

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Chapter 4.5, Problem 8SBE

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The way in which the relative intensities of two sounds compare.

Solution Summary: The author explains how the relative intensities of two sounds compare. The higher decibel sound is 1.58 times that of the lower one.

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To find: The way in which the relative intensities of two sounds compare.

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Chapter 4 Solutions

To find:

The way in which the relative intensities of two sounds compare.