Explanation Given info: lim → x 0 + ( Sin x x ) 1 x 2 Concept used: This limit is of form of ( 1 ) ∞ lim → x 0 + Sin x x = 1 lim → x 0 + 1 x 2 = ∞ exponential limit concept . Calculation: Let L = lim → x 0 + ( Sin x x ) 1 x 2 ( taking logarithm both side ) ln L = lim → x 0 + ln ( Sin x x ) 1 x 2 = lim → x 0 + 1 x 2 ln ( Sin x x ) = lim → x 0 + ln ( Sin x x ) x 2 ( this limit of the form of 0 0 , so apply L'Hospital rule ) = lim → x 0 + d d x ( Sin x x ) d d x ( x ) 2 ( Apply quotient rule of differentiation ) = lim → x 0 + x . d d x ( sin x ) − sin x . d x d x x 2 2 x = lim → x 0 + x Cos x − sin x 2 x 3 ( this limit is again of the form of 0 0 , so apply L'Hospital rule ) = lim → x 0 + d d x ( x Cos x − Sin x ) d d x ( 2 x ) 3 = lim → x 0 + x d Cos x d x + Cos x ... To determine (b) Use L ' Hospital rule to evaluate and check your answer numerically. lim → x 0 ( 1 Sin 2 x − 1 x 2 )

Loose-leaf Version for Calculus: Early Transcendentals Combo 3e & WebAssign for Calculus: Early Transcendentals 3e (Life of Edition)

3rd Edition

ISBN: 9781319019846

Author: Jon Rogawski, Colin Adams

Publisher: W. H. Freeman

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Question

Chapter 4.5, Problem 81E

To determine

(a)

Use $L'Hospital$ rule to evaluate and check your answer numerically

${}_{x}{\lim_{\to}}_{0^{+}} {(\frac{Sin x}{x})}^{\frac{1}{x^{2}}}$

To determine

(b)

Use $L' Hospital$ rule to evaluate and check your answer numerically.

${}_{x}{\lim_{\to}}_{0} (\frac{1}{{Sin}^{2} x} - \frac{1}{x^{2}})$

Expert Solution & Answer

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Chapter 4.5, Problem 80E

Chapter 4.5, Problem 82E

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Chapter 4 Solutions

Loose-leaf Version for Calculus: Early Transcendentals Combo 3e & WebAssign for Calculus: Early Transcendentals 3e (Life of Edition)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

Ch. 4.1 - Prob. 7E Ch. 4.1 - Prob. 8E Ch. 4.1 - Prob. 9E Ch. 4.1 - Prob. 10E Ch. 4.1 - Prob. 11E Ch. 4.1 - Prob. 12E Ch. 4.1 - Prob. 13E Ch. 4.1 - Prob. 14E Ch. 4.1 - Prob. 15E Ch. 4.1 - Prob. 16E Ch. 4.1 - Prob. 17E Ch. 4.1 - Prob. 18E Ch. 4.1 - Prob. 19E Ch. 4.1 - Prob. 20E Ch. 4.1 - Prob. 21E Ch. 4.1 - Prob. 22E Ch. 4.1 - Prob. 23E Ch. 4.1 - Prob. 24E Ch. 4.1 - Prob. 25E Ch. 4.1 - Prob. 26E Ch. 4.1 - Prob. 27E Ch. 4.1 - Prob. 28E Ch. 4.1 - Prob. 29E Ch. 4.1 - Prob. 30E Ch. 4.1 - Prob. 31E Ch. 4.1 - Prob. 32E Ch. 4.1 - Prob. 33E Ch. 4.1 - Prob. 34E Ch. 4.1 - Prob. 35E Ch. 4.1 - Prob. 36E Ch. 4.1 - Prob. 37E Ch. 4.1 - Prob. 38E Ch. 4.1 - Prob. 39E Ch. 4.1 - Prob. 40E Ch. 4.1 - Prob. 41E Ch. 4.1 - Prob. 42E Ch. 4.1 - Prob. 43E Ch. 4.1 - Prob. 44E Ch. 4.1 - Prob. 45E Ch. 4.1 - Prob. 46E Ch. 4.1 - Prob. 47E Ch. 4.1 - Prob. 48E Ch. 4.1 - Prob. 49E Ch. 4.1 - Prob. 50E Ch. 4.1 - Prob. 51E Ch. 4.1 - Prob. 52E Ch. 4.1 - Prob. 53E Ch. 4.1 - Prob. 54E Ch. 4.1 - Prob. 55E Ch. 4.1 - Prob. 56E Ch. 4.1 - 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Prob. 78E Ch. 4.3 - Prob. 79E Ch. 4.3 - Prob. 80E Ch. 4.3 - Prob. 81E Ch. 4.4 - Prob. 1PQ Ch. 4.4 - Prob. 2PQ Ch. 4.4 - Prob. 3PQ Ch. 4.4 - Prob. 4PQ Ch. 4.4 - Prob. 1E Ch. 4.4 - Prob. 2E Ch. 4.4 - Prob. 3E Ch. 4.4 - Prob. 4E Ch. 4.4 - Prob. 5E Ch. 4.4 - Prob. 6E Ch. 4.4 - Prob. 7E Ch. 4.4 - Prob. 8E Ch. 4.4 - Prob. 9E Ch. 4.4 - Prob. 10E Ch. 4.4 - Prob. 11E Ch. 4.4 - Prob. 12E Ch. 4.4 - Prob. 13E Ch. 4.4 - Prob. 14E Ch. 4.4 - Prob. 15E Ch. 4.4 - Prob. 16E Ch. 4.4 - Prob. 17E Ch. 4.4 - Prob. 18E Ch. 4.4 - Prob. 19E Ch. 4.4 - Prob. 20E Ch. 4.4 - Prob. 21E Ch. 4.4 - Prob. 22E Ch. 4.4 - Prob. 23E Ch. 4.4 - Prob. 24E Ch. 4.4 - Prob. 25E Ch. 4.4 - Prob. 26E Ch. 4.4 - Prob. 27E Ch. 4.4 - Prob. 28E Ch. 4.4 - Prob. 29E Ch. 4.4 - Prob. 30E Ch. 4.4 - Prob. 31E Ch. 4.4 - Prob. 32E Ch. 4.4 - Prob. 33E Ch. 4.4 - Prob. 34E Ch. 4.4 - Prob. 35E Ch. 4.4 - Prob. 36E Ch. 4.4 - Prob. 37E Ch. 4.4 - Prob. 38E Ch. 4.4 - Prob. 39E Ch. 4.4 - Prob. 40E Ch. 4.4 - Prob. 41E Ch. 4.4 - Prob. 42E Ch. 4.4 - Prob. 43E Ch. 4.4 - Prob. 44E Ch. 4.4 - Prob. 45E Ch. 4.4 - Prob. 46E Ch. 4.4 - Prob. 47E Ch. 4.4 - Prob. 48E Ch. 4.4 - Prob. 49E Ch. 4.4 - Prob. 50E Ch. 4.4 - Prob. 51E Ch. 4.4 - Prob. 52E Ch. 4.4 - Prob. 53E Ch. 4.4 - Prob. 54E Ch. 4.4 - Prob. 55E Ch. 4.4 - Prob. 56E Ch. 4.4 - Prob. 57E Ch. 4.4 - Prob. 58E Ch. 4.4 - Prob. 59E Ch. 4.4 - Prob. 60E Ch. 4.4 - Prob. 61E Ch. 4.4 - Prob. 62E Ch. 4.4 - Prob. 63E Ch. 4.4 - Prob. 64E Ch. 4.4 - Prob. 65E Ch. 4.4 - Prob. 66E Ch. 4.4 - Prob. 67E Ch. 4.4 - Prob. 68E Ch. 4.4 - Prob. 69E Ch. 4.4 - Prob. 70E Ch. 4.4 - Prob. 71E Ch. 4.4 - Prob. 72E Ch. 4.5 - Prob. 1PQ Ch. 4.5 - Prob. 2PQ Ch. 4.5 - Prob. 1E Ch. 4.5 - Prob. 2E Ch. 4.5 - Prob. 3E Ch. 4.5 - Prob. 4E Ch. 4.5 - Prob. 5E Ch. 4.5 - Prob. 6E Ch. 4.5 - Prob. 7E Ch. 4.5 - Prob. 8E Ch. 4.5 - Prob. 9E Ch. 4.5 - Prob. 10E Ch. 4.5 - Prob. 11E Ch. 4.5 - Prob. 12E Ch. 4.5 - Prob. 13E Ch. 4.5 - Prob. 14E Ch. 4.5 - Prob. 15E Ch. 4.5 - Prob. 16E Ch. 4.5 - Prob. 17E Ch. 4.5 - Prob. 18E Ch. 4.5 - Prob. 19E Ch. 4.5 - Prob. 20E Ch. 4.5 - 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Prob. 71E Ch. 4.5 - Prob. 72E Ch. 4.5 - Prob. 73E Ch. 4.5 - Prob. 74E Ch. 4.5 - Prob. 75E Ch. 4.5 - Prob. 76E Ch. 4.5 - Prob. 77E Ch. 4.5 - Prob. 78E Ch. 4.5 - Prob. 79E Ch. 4.5 - Prob. 80E Ch. 4.5 - Prob. 81E Ch. 4.5 - Prob. 82E Ch. 4.6 - Prob. 1PQ Ch. 4.6 - Prob. 2PQ Ch. 4.6 - Prob. 3PQ Ch. 4.6 - Prob. 1E Ch. 4.6 - Prob. 2E Ch. 4.6 - Prob. 3E Ch. 4.6 - Prob. 4E Ch. 4.6 - Prob. 5E Ch. 4.6 - Prob. 6E Ch. 4.6 - Prob. 7E Ch. 4.6 - Prob. 8E Ch. 4.6 - Prob. 9E Ch. 4.6 - Prob. 10E Ch. 4.6 - Prob. 11E Ch. 4.6 - Prob. 12E Ch. 4.6 - Prob. 13E Ch. 4.6 - Prob. 14E Ch. 4.6 - Prob. 15E Ch. 4.6 - Prob. 16E Ch. 4.6 - Prob. 17E Ch. 4.6 - Prob. 18E Ch. 4.6 - Prob. 19E Ch. 4.6 - Prob. 20E Ch. 4.6 - Prob. 21E Ch. 4.6 - Prob. 22E Ch. 4.6 - Prob. 23E Ch. 4.6 - Prob. 24E Ch. 4.6 - Prob. 25E Ch. 4.6 - Prob. 26E Ch. 4.6 - Prob. 27E Ch. 4.6 - Prob. 28E Ch. 4.6 - Prob. 29E Ch. 4.6 - Prob. 30E Ch. 4.6 - Prob. 31E Ch. 4.6 - Prob. 32E Ch. 4.6 - Prob. 33E Ch. 4.6 - Prob. 34E Ch. 4.6 - Prob. 35E Ch. 4.6 - Prob. 36E Ch. 4.6 - 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Knowledge Booster

(a) Use L'Hospital rule to evaluate and check your answer numerically lim → x 0 + ( Sin x x ) 1 x 2

(a) Use L'Hospital rule to evaluate and check your answer numerically lim→x0+(Sinxx)1x2

(b) Use L'Hospital rule to evaluate and check your answer numerically. lim→x0(1Sin2x−1x2)

Want to see the full answer?

Chapter 4 Solutions

(a)

Use $L'Hospital$ rule to evaluate and check your answer numerically

${}_{x}{\lim_{\to}}_{0^{+}} {(\frac{Sin x}{x})}^{\frac{1}{x^{2}}}$

(b)

Use $L' Hospital$ rule to evaluate and check your answer numerically.

${}_{x}{\lim_{\to}}_{0} (\frac{1}{{Sin}^{2} x} - \frac{1}{x^{2}})$