A mechanical metronome uses an inverted pendulum that makes a regular, rhythmic click as it swings to the left and right. With each swing, the pendulum moves 3 in . to the left and right of the center position. The pendulum is initially pulled to the right 3 in . and then released. It returns to its starting position in 0.8 sec. Assuming that this pattern continues indefinitely and behaves like a cosine wave, write a function of the form x t = A cos B t − C + D . The value x t is the horizontal position (in inches) relative to the center line of the pendulum.
A mechanical metronome uses an inverted pendulum that makes a regular, rhythmic click as it swings to the left and right. With each swing, the pendulum moves 3 in . to the left and right of the center position. The pendulum is initially pulled to the right 3 in . and then released. It returns to its starting position in 0.8 sec. Assuming that this pattern continues indefinitely and behaves like a cosine wave, write a function of the form x t = A cos B t − C + D . The value x t is the horizontal position (in inches) relative to the center line of the pendulum.
Solution Summary: The author explains that the value of x(t) is the horizontal position of a pendulum relative to the center line.
A mechanical metronome uses an inverted pendulum that makes a regular, rhythmic click as it swings to the left and right. With each swing, the pendulum moves
3
in
. to the left and right of the center position. The pendulum is initially pulled to the right
3
in
. and then released. It returns to its starting position in
0.8
sec. Assuming that this pattern continues indefinitely and behaves like a cosine wave, write a function of the form
x
t
=
A
cos
B
t
−
C
+
D
. The value
x
t
is the horizontal position (in inches) relative to the center line of the pendulum.
3.1 Limits
1. If lim f(x)=-6 and lim f(x)=5, then lim f(x). Explain your choice.
x+3°
x+3*
x+3
(a) Is 5
(c) Does not exist
(b) is 6
(d) is infinite
1 pts
Let F and G be vector fields such that ▼ × F(0, 0, 0) = (0.76, -9.78, 3.29), G(0, 0, 0) = (−3.99, 6.15, 2.94), and
G is irrotational. Then sin(5V (F × G)) at (0, 0, 0) is
Question 1
-0.246
0.072
-0.934
0.478
-0.914
-0.855
0.710
0.262
.
2. Answer the following questions.
(A) [50%] Given the vector field F(x, y, z) = (x²y, e", yz²), verify the differential identity
Vx (VF) V(V •F) - V²F
(B) [50%] Remark. You are confined to use the differential identities.
Let u and v be scalar fields, and F be a vector field given by
F = (Vu) x (Vv)
(i) Show that F is solenoidal (or incompressible).
(ii) Show that
G =
(uvv – vVu)
is a vector potential for F.
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