Biostatistics for the Biological and Health Sciences
Biostatistics for the Biological and Health Sciences
2nd Edition
ISBN: 9780134679235
Author: Triola
Publisher: PEARSON
Question
Book Icon
Chapter 4.5, Problem 21SLCT
To determine

To find the Florida mortality rate from adjusted data and compare it with mortality rate for the United States.

Expert Solution & Answer
Check Mark

Explanation of Solution

Given:

     Age 
     0-2425-6465 and olderTotal
    Florida deaths362539820129395172840
    Florida population57168619842031337530318934195
    U.S. deaths 6320861998218322682515458
    U.S. population10354260316396016345296729312799495
    Total10932629717446199650633695334421988

Now, first need to calculate the U.S. population distribution for the age groups:

For age group 0-24:

U.S. population proportion for group 0-24:

  U.S. population proportion for group 024=populationin024agegroupPopulationsize=103542603312799495=33.10%

Using above formula, we can find U.S. population proportion for age group 24-64

= 54.41%

U.S. population proportion for age group 64 and older

= 14.48%

Now, we can find the population distribution of Florida with respect to the population distribution for different age groups of U.S.:

For age group 0-24:

  Florida population proportion for group 024=U.S. population proportion for group 024populationin024agegroupPopulationsizeofFlorida%=33.10%populationin024agegroup18934195=0.3310populationin024agegroup=6267580

Population for age group 24-64 for Florida: 9924740

Population for age group 64 and older for Florida:2741875

Now, we will compute the mortality rate for Florida with respect to the U.S. age group.

  Florida mortality rate for age 024=Numberofdeathsin024agegroupOldpopulationofFloridain024agegroup×1000=36255716861×1000=0.6

By using same formula, we can calculate,

Florida mortality rate for age 24-64=4.0

Florida mortality rate for age 64 and older=38.3

Now, we will calculate the number of deaths in Florida with respect to the new population distribution using the mortality rate.

  Florida mortality rate for age 024=Newnumberofdeathsin024agegroupNewpopulationofFloridain024agegroup0.6=Newnumberofdeathsin024agegroup6267580Newnumberofdeathsin024agegroup=2974

Using same formula,

New number of deaths in 24-64 age group=40155

New number of deaths in 64 and older age group=105112

Therefore, new calculated data is,

    Age
    0-2425-6465 and olderTotal
    Florida deaths397440155105112149241
    Florida population626758099247401893419535126515
    U.S. deaths 6320861998218322682515458
    U.S. population10354260316396016345296729312799495
    Total10987736517454504066168304350590709

We know crude mortality rate from old data is,

Crude mortality rate of U.S. = 8

Crude mortality rate of Florida = 9.1

Therefore, using new data,

Crude mortality rate for U.S. = 8

Crude mortality rate for Florida = 7.9

Hence, new adjusted crude mortality rate of Florida us much closer to the Crude mortality rate for U.S. As there was difference in old data.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Elementary StatisticsBase on the same given data uploaded in module 4, will you conclude that the number of bathroom of houses is a significant factor for house sellprice? I your answer is affirmative, you need to explain how the number of bathroom influences the house price, using a post hoc procedure. (Please treat number of bathrooms as a categorical variable in this analysis)Base on the same given data, conduct an analysis for the variable sellprice to see if sale price is influenced by living area. Summarize your finding including all regular steps (learned in this module) for your method. Also, will you conclude that larger house corresponding to higher price (justify)?Each question need to include a spss or sas output.       Instructions: You have to use SAS or SPSS to perform appropriate procedure: ANOVA or Regression based on the project data (provided in the module 4) and research question in the project file. Attach the computer output of all key steps (number) quoted in…
Elementary StatsBase on the given data uploaded in module 4, change the variable sale price into two categories: abovethe mean price or not; and change the living area into two categories: above the median living area ornot ( your two group should have close number of houses in each group). Using the resulting variables,will you conclude that larger house corresponding to higher price?Note: Need computer output, Ho and Ha, P and decision. If p is small, you need to explain what type ofdependency (association) we have using an appropriate pair of percentages.       Please include how to use the data in SPSS and interpretation of data.
An environmental research team is studying the daily rainfall (in millimeters) in a region over 100 days. The data is grouped into the following histogram bins: Rainfall Range (mm) Frequency 0-9.9 15 10 19.9 25 20-29.9 30 30-39.9 20 ||40-49.9 10 a) If a random day is selected, what is the probability that the rainfall was at least 20 mm but less than 40 mm? b) Estimate the mean daily rainfall, assuming the rainfall in each bin is uniformly distributed and the midpoint of each bin represents the average rainfall for that range. c) Construct the cumulative frequency distribution and determine the rainfall level below which 75% of the days fall. d) Calculate the estimated variance and standard deviation of the daily rainfall based on the histogram data.

Chapter 4 Solutions

Biostatistics for the Biological and Health Sciences

Ch. 4.1 - Prob. 11SLCTCh. 4.1 - Prob. 12SLCTCh. 4.1 - Prob. 13SLCTCh. 4.1 - Prob. 14SLCTCh. 4.1 - Prob. 15SLCTCh. 4.1 - Prob. 16SLCTCh. 4.1 - Prob. 17SLCTCh. 4.1 - Prob. 18SLCTCh. 4.1 - Prob. 19SLCTCh. 4.1 - Prob. 20SLCTCh. 4.1 - Prob. 21SLCTCh. 4.1 - Prob. 22SLCTCh. 4.1 - Prob. 23SLCTCh. 4.1 - Prob. 24SLCTCh. 4.1 - Prob. 25SLCTCh. 4.1 - Prob. 26SLCTCh. 4.1 - Prob. 27SLCTCh. 4.1 - Prob. 28SLCTCh. 4.1 - Prob. 29SLCTCh. 4.1 - Prob. 30SLCTCh. 4.1 - Prob. 31SLCTCh. 4.1 - Prob. 32SLCTCh. 4.1 - Prob. 33SLCTCh. 4.1 - Prob. 34SLCTCh. 4.1 - Prob. 35SLCTCh. 4.1 - Prob. 36SLCTCh. 4.1 - Prob. 37SLCTCh. 4.1 - Prob. 38SLCTCh. 4.1 - Prob. 39SLCTCh. 4.1 - Prob. 40SLCTCh. 4.2 - Prob. 1SLCTCh. 4.2 - Prob. 2SLCTCh. 4.2 - Prob. 3SLCTCh. 4.2 - Prob. 4SLCTCh. 4.2 - Prob. 5SLCTCh. 4.2 - Prob. 6SLCTCh. 4.2 - Prob. 7SLCTCh. 4.2 - Prob. 8SLCTCh. 4.2 - Prob. 9SLCTCh. 4.2 - Prob. 10SLCTCh. 4.2 - Prob. 11SLCTCh. 4.2 - Prob. 12SLCTCh. 4.2 - Prob. 13SLCTCh. 4.2 - Prob. 14SLCTCh. 4.2 - Prob. 15SLCTCh. 4.2 - Prob. 16SLCTCh. 4.2 - Prob. 17SLCTCh. 4.2 - Prob. 18SLCTCh. 4.2 - Prob. 19SLCTCh. 4.2 - Prob. 20SLCTCh. 4.2 - Prob. 21SLCTCh. 4.2 - Prob. 22SLCTCh. 4.2 - Prob. 23SLCTCh. 4.2 - Prob. 24SLCTCh. 4.2 - Prob. 25SLCTCh. 4.2 - Prob. 26SLCTCh. 4.2 - Prob. 27SLCTCh. 4.2 - Prob. 28SLCTCh. 4.2 - Prob. 29SLCTCh. 4.2 - Prob. 30SLCTCh. 4.2 - Prob. 31SLCTCh. 4.2 - Prob. 32SLCTCh. 4.2 - Prob. 33SLCTCh. 4.2 - Prob. 34SLCTCh. 4.3 - Prob. 1SLCTCh. 4.3 - Prob. 2SLCTCh. 4.3 - Prob. 3SLCTCh. 4.3 - Prob. 4SLCTCh. 4.3 - Prob. 5SLCTCh. 4.3 - Prob. 6SLCTCh. 4.3 - Prob. 7SLCTCh. 4.3 - Prob. 8SLCTCh. 4.3 - Prob. 9SLCTCh. 4.3 - Prob. 10SLCTCh. 4.3 - Prob. 11SLCTCh. 4.3 - Prob. 12SLCTCh. 4.3 - Prob. 13SLCTCh. 4.3 - Prob. 14SLCTCh. 4.3 - Prob. 15SLCTCh. 4.3 - Prob. 16SLCTCh. 4.3 - Prob. 17SLCTCh. 4.3 - Prob. 18SLCTCh. 4.3 - Prob. 19SLCTCh. 4.3 - Prob. 20SLCTCh. 4.3 - Prob. 21SLCTCh. 4.3 - Prob. 22SLCTCh. 4.3 - Prob. 23SLCTCh. 4.3 - Prob. 24SLCTCh. 4.3 - Prob. 25SLCTCh. 4.4 - Prob. 1SLCTCh. 4.4 - Prob. 2SLCTCh. 4.4 - Prob. 3SLCTCh. 4.4 - Prob. 4SLCTCh. 4.4 - Prob. 5SLCTCh. 4.4 - Prob. 6SLCTCh. 4.4 - Prob. 7SLCTCh. 4.4 - Prob. 8SLCTCh. 4.4 - Prob. 9SLCTCh. 4.4 - Prob. 10SLCTCh. 4.4 - Prob. 11SLCTCh. 4.4 - Prob. 12SLCTCh. 4.4 - Prob. 13SLCTCh. 4.4 - Prob. 14SLCTCh. 4.4 - Prob. 15SLCTCh. 4.4 - Prob. 16SLCTCh. 4.4 - Prob. 17SLCTCh. 4.4 - Prob. 18SLCTCh. 4.5 - Prob. 1SLCTCh. 4.5 - Prob. 2SLCTCh. 4.5 - Prob. 3SLCTCh. 4.5 - Prob. 4SLCTCh. 4.5 - Prob. 5SLCTCh. 4.5 - Prob. 6SLCTCh. 4.5 - Prob. 7SLCTCh. 4.5 - Prob. 8SLCTCh. 4.5 - Prob. 9SLCTCh. 4.5 - Prob. 10SLCTCh. 4.5 - Prob. 11SLCTCh. 4.5 - Prob. 12SLCTCh. 4.5 - Prob. 13SLCTCh. 4.5 - Prob. 14SLCTCh. 4.5 - Prob. 15SLCTCh. 4.5 - Prob. 16SLCTCh. 4.5 - Prob. 17SLCTCh. 4.5 - Prob. 18SLCTCh. 4.5 - Prob. 19SLCTCh. 4.5 - Prob. 20SLCTCh. 4.5 - Prob. 21SLCTCh. 4.6 - Prob. 1SLCTCh. 4.6 - Prob. 2SLCTCh. 4.6 - Prob. 3SLCTCh. 4.6 - Prob. 4SLCTCh. 4.6 - Prob. 5SLCTCh. 4.6 - Prob. 6SLCTCh. 4.6 - Prob. 7SLCTCh. 4.6 - Prob. 8SLCTCh. 4.6 - Prob. 9SLCTCh. 4.6 - Prob. 10SLCTCh. 4.6 - Prob. 11SLCTCh. 4.6 - Prob. 12SLCTCh. 4.6 - Prob. 13SLCTCh. 4.6 - Prob. 14SLCTCh. 4.6 - Prob. 15SLCTCh. 4.6 - Prob. 16SLCTCh. 4.6 - Prob. 17SLCTCh. 4.6 - Prob. 18SLCTCh. 4.6 - Prob. 19SLCTCh. 4.6 - Prob. 20SLCTCh. 4.6 - Prob. 21SLCTCh. 4.6 - Prob. 22SLCTCh. 4.6 - Prob. 23SLCTCh. 4.6 - Prob. 24SLCTCh. 4.6 - Prob. 25SLCTCh. 4.6 - Prob. 26SLCTCh. 4.6 - Prob. 27SLCTCh. 4.6 - Prob. 28SLCTCh. 4.6 - Prob. 29SLCTCh. 4.6 - Prob. 30SLCTCh. 4.6 - Prob. 31SLCTCh. 4.6 - Prob. 32SLCTCh. 4 - Prob. 1CQQCh. 4 - Prob. 2CQQCh. 4 - Prob. 3CQQCh. 4 - Prob. 4CQQCh. 4 - Prob. 5CQQCh. 4 - Prob. 6CQQCh. 4 - Prob. 7CQQCh. 4 - Prob. 8CQQCh. 4 - Prob. 9CQQCh. 4 - Prob. 10CQQCh. 4 - Prob. 1RECh. 4 - Prob. 2RECh. 4 - Prob. 3RECh. 4 - Prob. 4RECh. 4 - Prob. 5RECh. 4 - Prob. 6RECh. 4 - Prob. 7RECh. 4 - Prob. 8RECh. 4 - Prob. 9RECh. 4 - Prob. 10RECh. 4 - Prob. 11RECh. 4 - Prob. 12RECh. 4 - Prob. 13RECh. 4 - Prob. 14RECh. 4 - Prob. 1CRECh. 4 - Prob. 2CRECh. 4 - Prob. 3CRECh. 4 - Prob. 4CRECh. 4 - Prob. 5CRE
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Text book image
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Text book image
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Text book image
Functions and Change: A Modeling Approach to Coll...
Algebra
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Cengage Learning
Text book image
Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
Text book image
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell