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Chapter 44, Problem 6P
To determine

The reason why out of the two given reactions only first one can occur while the second one is forbidden.

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1) For each of the following reactions work out the fastest interaction through which the conservation laws allow it to proceed. Explain your answers. If the reaction is forbidden by all interactions explain why: -+ a. pn++μ+ +μ¯ b. Aºp+e¯ c. μ΄ →e + V d. p+p→y+Y e. Kºn++ π + π° +7° f. π+pAº + Kº g. Aºn+p h. pnº+e+ + ve i. n→p+e+V₂
The first of the following two reactions can occur, but thesecond cannot. Explain.KS0 → π+ + π-                             (can occur)L0  → π+ + π-                              (cannot occur)
Determine which of the following reactions can occur. For those that cannot occur, determine the conservation law (or laws) violated. (a) p→ ㅠ + mo (b) p + p → p + p + 7° (c) p+p - p+ n* (e) n → p+e- + ī, (d) * → ut + v. (f) → ut + n
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