Explanation Given: The provided integral is ∫ 0 ∞ e − 2 t t sin 4 t d t . Definition used: (1) The formula for the Laplace of f ( t ) is defined below, L { f ( t ) } = ∫ 0 ∞ e − s t f ( t ) d t F ( s ) = ∫ 0 ∞ e − s t f ( t ) d t (2) The convolution theorem of inverse Laplace is mention below as, L − 1 { f ∗ g } = L − 1 { f ( t ) } L − 1 { g ( t ) } = F ( s ) G ( s ) Calculation: Consider a function f ( t ) as follows: f ( t ) = t sin 4 t ....

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ISBN: 9781284127003

Author: ZILL

Publisher: JONES+BARTLETT LEARNING,LLC (CC)

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Chapter 4.4, Problem 65E

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The value of integral ∫0∞e−2ttsin4tdt using Laplace transform.

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Chapter 4.4, Problem 64E

Chapter 4.4, Problem 66E

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The value of integral ∫ 0 ∞ e − 2 t t sin 4 t d t using Laplace transform.

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The value of integral ∫0∞e−2ttsin4tdt using Laplace transform.

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Chapter 4 Solutions