Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 44, Problem 65AP
To determine
Find the time at which the stars explode and released the elements that formed the Earth.
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The theory of nuclear astrophysics is that all the heavy elements like uranium are formed in the interior of massive stars. These stars eventually explode, releasing the elements into space. If we assume that at the time of explosion there were equal amounts of 235U and 238U, how long ago were the elements that formed our Earth released, given that the present 235U/238U ratio is 0.007? (The half-lives of 235U and 238U are 0.70 x 109 yr and 4.47 x 109 yr, respectively.)
Consider the following decay: 232 U
92
a mass of 4.002603 u.
228 Th+ a. 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has
90
92
90
A.) Determine the disintegration energy (Q-value) in MeV.
Q=
B.) Determine the KE of the daughter in MeV.
KED=
C.) Determine the KE of the a particle in MeV & as a factor of Q.
KE=
KE=Qx
D.) Determine the speed of the particle in terms of c. For an a particle, E = 3.727 GeV. [NOTE: G stands for giga- which means 10º & M
stands for mega- which means 106.]
Vα =
XC
Consider the following decay:
232 U →
228 Th + a .
232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has a mass of 4.002603 u.
92
90
92
90
Determine the disintegration energy (Q-value) in MeV.
Q =
Determine the KE of the daughter in MeV.
KED =
Determine the KE of the a particle in MeV & as a factor of Q.
KE, =
KEa
= Qx
Determine the speed of the a particle in terms of c. For an a particle, E. = 3.727 GeV. [NOTE: G stands for giga- which means 109 & M stands for mega- which means 10°.]
Valpha =
XC
Chapter 44 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 44.1 - Prob. 44.1QQCh. 44.5 - Prob. 44.3QQCh. 44.5 - Which of the following is the correct daughter...Ch. 44 - Prob. 1OQCh. 44 - Prob. 2OQCh. 44 - Prob. 3OQCh. 44 - Prob. 4OQCh. 44 - Prob. 5OQCh. 44 - Prob. 6OQCh. 44 - Prob. 7OQ
Ch. 44 - Prob. 8OQCh. 44 - Prob. 9OQCh. 44 - Prob. 10OQCh. 44 - Prob. 11OQCh. 44 - Prob. 12OQCh. 44 - Prob. 13OQCh. 44 - Prob. 1CQCh. 44 - Prob. 2CQCh. 44 - Prob. 3CQCh. 44 - Prob. 4CQCh. 44 - Prob. 5CQCh. 44 - Prob. 6CQCh. 44 - Prob. 7CQCh. 44 - Prob. 8CQCh. 44 - Prob. 9CQCh. 44 - Prob. 10CQCh. 44 - Prob. 11CQCh. 44 - Prob. 12CQCh. 44 - Prob. 13CQCh. 44 - Prob. 14CQCh. 44 - Prob. 15CQCh. 44 - Prob. 16CQCh. 44 - Prob. 17CQCh. 44 - Prob. 1PCh. 44 - Prob. 2PCh. 44 - Prob. 3PCh. 44 - Prob. 4PCh. 44 - Prob. 5PCh. 44 - Prob. 6PCh. 44 - Prob. 7PCh. 44 - Prob. 8PCh. 44 - Prob. 9PCh. 44 - Prob. 10PCh. 44 - Prob. 11PCh. 44 - Prob. 12PCh. 44 - Prob. 13PCh. 44 - Prob. 14PCh. 44 - Prob. 15PCh. 44 - Prob. 16PCh. 44 - Prob. 17PCh. 44 - Prob. 18PCh. 44 - Prob. 19PCh. 44 - Prob. 20PCh. 44 - Prob. 21PCh. 44 - Prob. 22PCh. 44 - Prob. 23PCh. 44 - Prob. 24PCh. 44 - Prob. 25PCh. 44 - Prob. 26PCh. 44 - Prob. 27PCh. 44 - Prob. 28PCh. 44 - Prob. 29PCh. 44 - Prob. 31PCh. 44 - Prob. 32PCh. 44 - Prob. 33PCh. 44 - Prob. 34PCh. 44 - Prob. 35PCh. 44 - Prob. 36PCh. 44 - Prob. 37PCh. 44 - Prob. 38PCh. 44 - Prob. 39PCh. 44 - Prob. 40PCh. 44 - Prob. 41PCh. 44 - Prob. 42PCh. 44 - Prob. 43PCh. 44 - Prob. 44PCh. 44 - Prob. 45PCh. 44 - Prob. 46PCh. 44 - Prob. 47PCh. 44 - Prob. 48PCh. 44 - Prob. 49PCh. 44 - Prob. 50PCh. 44 - Prob. 51PCh. 44 - Prob. 52PCh. 44 - Prob. 53PCh. 44 - Prob. 54APCh. 44 - Prob. 55APCh. 44 - Prob. 56APCh. 44 - Prob. 57APCh. 44 - Prob. 58APCh. 44 - Prob. 59APCh. 44 - Prob. 60APCh. 44 - Prob. 61APCh. 44 - Prob. 62APCh. 44 - Prob. 63APCh. 44 - Prob. 64APCh. 44 - Prob. 65APCh. 44 - Prob. 66APCh. 44 - Prob. 67APCh. 44 - Prob. 68APCh. 44 - Prob. 69APCh. 44 - Prob. 70APCh. 44 - Prob. 71APCh. 44 - Prob. 72APCh. 44 - As part of his discovery of the neutron in 1932,...Ch. 44 - Prob. 74APCh. 44 - Prob. 75APCh. 44 - Prob. 76APCh. 44 - Prob. 77CPCh. 44 - Prob. 78CP
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- (a) Write the complete + decay equation for llC. (b) Calculate the energy released in the decay. The masses of 11C and 11B are 11.011433 and 11.009305 u, respectively.arrow_forwardThe electrical power output of a large nuclear reactor facility is 900 MW. It has a 35.0% efficiency in converting nuclear power to electrical. (a) What is the thermal nuclear power output in megawatts? (b) How many 235U nuclei fission each second, assuming the average fission produces 200 MeV? (c) What mass of 235U is fissioned in one year of fullpower operation?arrow_forwardThe K0 meson is an uncharged member of the particle “zoo” that decays into two charged pions according to K0 → π+ + π−. The pions have opposite charges, as indicated, and the same mass, mπ = 140 MeV/c2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0 T is present (see Fig. P2.22). If the radius of curvature of the pions is 34.4 cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.arrow_forward
- (a) Write the decay equation for the decay of 235U. (b) What energy is released in this decay? The mass of the daughter nuclide is 231.036298 u. (c) Assuming the residual nucleus is formed in its ground state, how much energy goes to the particle?arrow_forwardCalculate the energy released in the + decay of 22Na, the equation for which is given in the text. The masses at 22Na and 22Ne are 21.994434 and 21.991333 u, reSpec?vely.arrow_forwardThe primary decay mode for the negative pion is +v . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E/c , just like a photon.arrow_forward
- (a) Calculate the energy released in the a decay of 238U. (b) What fraction of the mass at a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is laws for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forwardIf 1.01030MeV of energy is released in the annihilation of a sphere of matter and antimatter, and the spheres are equal mass, what are the masses of the spheres?arrow_forwardDerive an approximate relationship between the energy of (decay and halflife using the following data. It may be useful to graph the leg t1/2 against Ea to find some straightline relationship. Table 31.3 Energy and HalfLife for (Decay Nuclide E( (MeV) t1/2 216Ra 9.5 0.18 (s 194Po 7.0 0.7 s 240Cm 6.4 27 d 226Ra 4.91 1600 y 232Th 4.1 1.41010yarrow_forward
- The primary decay mode for the negative pion is What is the energy release in MeV in this decay?arrow_forwardIf the rest energies of a proton and a neutron (the two constituents of nuclei) are 938.3 and 939.6 MeV, what is the difference in their mass in kilograms?arrow_forward(a) Estimate the mass of the luminous matter in the known universe, given there are 1011 galaxies, each containing 1011 stars of average mass 1.5 times that of our Sun. (b) How many protons (the most abundant nuclide) are there in this mates? (c) Estimate the total number of particles in the observable universe by multiplying the answer to (b) by two, since there is an electron for each proton, and then by 109, since there are far more particles (such as photons and neutrinos) in space than in luminous matter.arrow_forward
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