Chapter 4.4, Problem 49E

To determine

To order the number from least to greatest.

Answer to Problem 49E

  $\frac{1}{5}<\frac{3}{10}<\frac{8}{15}$ .

Explanation of Solution

Given information: $\frac{8}{15},\frac{1}{5},\frac{3}{10}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 15, 5 and 10 is 30

So , denominator of both fractions 30.

  $\frac{8\times 2}{15\times 2}=\frac{16}{30}$

  $\frac{1\times 6}{5\times 6}=\frac{6}{30}$

  $\frac{3\times 3}{10\times 3}=\frac{9}{30}$

  $\frac{6}{30}<\frac{9}{30}<\frac{16}{30}$

So, $\frac{1}{5}<\frac{3}{10}<\frac{8}{15}$ .