Use Exercise 48 to show that every integer of the form ( 6 m + 1 ) ( 12 m + 1 ) ( 18 m + 1 ) , where m is a positive integer and 6 m + 1 , 12 m + 1 , and 18 m + 1 are all primes, is a Carmichael number Use part(a) to show that 172,947,529 is a Carmichael number.
Use Exercise 48 to show that every integer of the form ( 6 m + 1 ) ( 12 m + 1 ) ( 18 m + 1 ) , where m is a positive integer and 6 m + 1 , 12 m + 1 , and 18 m + 1 are all primes, is a Carmichael number Use part(a) to show that 172,947,529 is a Carmichael number.
Solution Summary: The author concludes that n is a Carmichael number by using Exercise 48.
Use Exercise 48 to show that every integer of the form
(
6
m
+
1
)
(
12
m
+
1
)
(
18
m
+
1
)
, where m is a positive integer and
6
m
+
1
,
12
m
+
1
, and
18
m
+
1
are all primes, is a Carmichael number
Use part(a) to show that 172,947,529 is a Carmichael number.
By considering appropriate series expansions,
e². e²²/2. e²³/3.
....
=
= 1 + x + x² + ·
...
when |x| < 1.
By expanding each individual exponential term on the left-hand side
the coefficient of x- 19 has the form
and multiplying out,
1/19!1/19+r/s,
where 19 does not divide s. Deduce that
18! 1 (mod 19).
Proof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.
By considering appropriate series expansions,
ex · ex²/2 . ¸²³/³ . . ..
=
= 1 + x + x² +……
when |x| < 1.
By expanding each individual exponential term on the left-hand side
and multiplying out, show that the coefficient of x 19 has the form
1/19!+1/19+r/s,
where 19 does not divide s.
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