Building Java Programs: A Back To Basics Approach, Loose Leaf Edition (5th Edition)
Building Java Programs: A Back To Basics Approach, Loose Leaf Edition (5th Edition)
5th Edition
ISBN: 9780135472118
Author: Stuart Reges, Marty Stepp
Publisher: PEARSON
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Chapter 4.4, Problem 29SCP

Explanation of Solution

Fixing the code

  • The code fails when more than one number is odd, because it uses else if instead of if.
  • The test should not be nested because they are not mutually exclusive and more than one number could be odd.
  • The code that fixes the problem is:

    public static void printNumOdd(int n1, int n2, int n3)

    {

    int count = 0;

    if (n1 % 2 != 0)

    {

  count++;

  }

  if (n2 % 2 != 0)...

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Write a c++ program that will count from 1 to 10 by 1. The default output should be: 1, 2, 3, 4, 5, 6 , 7, 8, 9, 10 There should be only a newline after the last number. Each number except the last should be followed by a comma and a space. To make your program more functional, you should parse command line arguments and change behavior based on their values. Argument Parameter Action -f, --first yes, an integer Change place you start counting -l, --last yes, an integer Change place you end counting -s, --skip optional, an integer, 1 if not specified Change the amount you add to the counter each iteration -h, —help none Print a help message including these instructions. -j, --joke none Tell a number based joke. So, if your program is called counter, counter -f 10 --last 4 --skip 2 should produce 10, 8, 6, 4 Please use the last supplied argument. If your code is called counter, counter -f 4 -f 5 -f 6 should count from 6. You should…
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Building Java Programs: A Back To Basics Approach, Loose Leaf Edition (5th Edition)

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