the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Question

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Answer 1

Question

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

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6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from diffraction limited, with a spot size of more than 100 microns. Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert one extra line at the top of the merit function. Assign the…

Answer 2

Question

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

Answer 6

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

Answer 7

Chapter 44, Problem 1Q

To determine

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Answer 8

Expert Solution & Answer

Answer to Problem 1Q

Solution:

An electron cannot decay into two neutrinos because this decay violates angular momentum, charge and lepton number conservation laws. Also electrons and neutrinos are not baryons, and therefore baryon number conservation law cannot be applied to this decay.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

The list of conservation laws that are given is:

a) Energy

b) Angular momentum

c) Charge

d) Lepton number

e) Linear momentum

f) Baryon number

When you look at this equation

e^- ν + ν

you will immediately see that the charge, and the lepton number conservation laws are violated. But there are other laws that are violated too.

Let us look at the conservation laws in details:

i. If you look at the angular momentum (spin) both, an electron and a neutrino have spin ½; hence (b) that is angular momentum conservation law is violated.

ii. Neutrinos carry no charge, hence (c) that is charge conservation law is not obeyed.

iii. Lepton number of an electron is +1, and for neutrinos is +1 too, hence (d) that is lepton number conservation law is violated. Even if you consider antineutrino-neutrino pair on the right hand side, the lepton number conservation law will be violated.

iv. Electrons and neutrinos are leptons and not baryons; thus the baryon number conservation law (f) does not come into picture at all.

We cannot say anything about the energy and linear momentum conservation laws because electron anyway does not decay into two neutrinos.

Conclusion

Theoretically, a charge is always conserved and thus electron is a completely stable particle.

Answer 12

Ch. 44 - Prob. 1Q Ch. 44 - Prob. 2Q Ch. 44 - Prob. 3Q Ch. 44 - Prob. 4Q Ch. 44 - Prob. 5Q Ch. 44 - Prob. 6Q Ch. 44 - Prob. 7Q Ch. 44 - Prob. 8Q Ch. 44 - Prob. 9Q Ch. 44 - Prob. 10Q

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Concept explainers

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Answer to Problem 1Q

Explanation of Solution

Want to see more full solutions like this?

Chapter 44 Solutions

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Concept explainers

To find: the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.

Answer to Problem 1Q

Explanation of Solution

Want to see more full solutions like this?

Chapter 44 Solutions

To find:

the conservation laws that are violated for an electron to decay into two neutrinos, from a given list of conservation laws.