Chapter 4.4, Problem 13E

To determine

To find LCD

Answer to Problem 13E

  $\frac{2}{5}$ is greater than $\frac{3}{8}$ .

Explanation of Solution

Given information: $\frac{2}{5},\frac{3}{8}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 5 and 8 is 40

So ,denominator of both fractions 40.

  $\frac{2\times 8}{5\times 8}=\frac{16}{40}$

  $\frac{3\times 5}{8\times 5}=\frac{15}{40}$

  $\frac{16}{40}>\frac{15}{40}$

So, $\frac{2}{5}$ is greater than $\frac{3}{8}$ .