To show that: (a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by K p = ½ kT Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10 7 K. (b) the most probable speed is given by v p = 2 k T m , then find its value for protons at T = 1.5x10 7 K. (c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is K v, p = kT And locate this quantity of the curve given in Fig 43.10.

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Answer 1

Question

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

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Answer 2

Question

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Answer 6

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Answer 7

Chapter 43, Problem 56P

To determine

To show that:

(a) if the expressions for Maxwell’s speed distribution energies for molecules in a gas is as given in Chapter 19, then the most probable energy is given by

K_p = ½ kT

Also verify the result with the energy distribution curve given in Fig 43.10 in the textbook, for T = 1.5x10⁷K.

(b) the most probable speed is given by

vp= 2kTm,

then find its value for protons at T = 1.5x10⁷K.

(c) the energy corresponding to the most probable speed (which is not the same as most probable energy) is

K_{v, p} = kT

And locate this quantity of the curve given in Fig 43.10.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 43 - Prob. 1Q Ch. 43 - Prob. 2Q Ch. 43 - Prob. 3Q Ch. 43 - Prob. 4Q Ch. 43 - Prob. 5Q Ch. 43 - Prob. 6Q Ch. 43 - Prob. 7Q Ch. 43 - Which of these elements is not cooked up by...Ch. 43 - Prob. 9Q Ch. 43 - Prob. 10Q

Solution Summary: The author explains Maxwell's speed distribution energies for molecules in a gas as given in Chapter 19. The most probable energy is given by K p = 12 kT, and the energy corresponding to the most

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Chapter 43 Solutions