Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Concept explainers
Question
Chapter 43, Problem 1SQ
a.
To determine
Draw the diagram of series motor.
a.
Expert Solution
Explanation of Solution
DC motor:
A DC motor is an electrical rotary machine that is used to convert electrical power into
Series motor:
In the series motor, the field winding and armature winding are connected in series. Since the field and armature winding are in series, it should be large enough to carry the current of the armature circuit. The diagram of series motor is shown in Figure 1. The series field winding is represented as
Conclusion:
Thus, the diagram of series motor is drawn.
b.
To determine
Draw the diagram of shunt motor.
b.
Expert Solution
Explanation of Solution
Shunt motor:
In the shunt motor, the field and armature winding are in parallel connection. The rheostat is connected in series with field winding to vary the resistance of field circuit. The diagram of shunt motor is shown in Figure 2. The shunt connected field winding is represented as
Conclusion:
Thus, the diagram of shunt motor is drawn.
c.
To determine
Draw the diagram of compound motor.
c.
Expert Solution
Explanation of Solution
Compound motor:
The compound motor has both a series and shunt field winding. The diagram of compound motor is shown in Figure 3.
Conclusion:
Thus, the diagram of compound motor is drawn.
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2. Suppose
G₁(s) = (s+2)
G₂(s) = (s-3)
C(s)
Find the transfer function G(s):
for each of the following three configurations
R(s)
shown in Figure 1. Note (a) is a cascaded (series) system, (b) is a parallel system, and
(c) is a feedback (closed-loop) system.
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(c)
C(s)
R(s)
G₁(s)
G2(5)
G₁(s)
R(s)
C(s)
G2(s)
C(s)
R(s)
G₁(s)
G₂(s)
Figure 1
Determine the transformer's active power losses and primary voltage (Figure 1). The
busbar's voltage at the transformer's secondary side is 20.5 kV. Load P is 6 MW, and the
power factor is 0.95ind.
Select a short-circuit withstanding (1-second short circuit length) cable for Feeder 1 in
Figure 1. Values for cables are given in Table 1. The voltage of the supplying network is
now 115 kV and the short-circuit power of the supplying network is 2000 MVA.
Table 1. Technical information of 3-phase cables (10 kV and 20 kV)
Product's name
EA-number
Structural information
20KV
20KV
20 KV
0624250
0624252
0624253
0624254
AHKAMK-W AHKAMKW AHKAMKWAHKAMKW AHKAMKW AHKAMKW AHKAMKW
3x50Al+35Cu 3x95 Al. 35Cu 3x120Al. 35Cu 3x150Al+35Cu 3x185Al+35Cu 3x240A1+70 Cu 3x300Al+70Cu
20kV
20kV 20 kV (8) 20KV
0624255
0624257
0624256
Diameter of conductor
Diameter of out-most circle
Cable's outer diameter
Mass
Delivery information
Standard length
Delivery reel
mm
8.0
11.3
12.7
14.1
15.7
18.1
20.3
mm
28
32
34
35
37
40
43
mm
64
71
74
76
80
89
94
aluminium
kg/km
510
910
1100
1350
1650
2200
2700
сорраг
kg/km
305
305
305
305
305
600
600
cable
kg/km
2350
3100
3450
3800
4300
5500
6250
E
500
500
500
500
500
500
500…
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