The tabulated values of height, h , when the basketball is thrown upward with the initial velocity 79 feet per second, and complete the table given below such that the height as a function of time is represented as h t = − 16 t 2 + 79 t + 5 , t 0 1 2 3 4 5 h Also, from the above table, determine whether the basketball reaches the height of 110 feet or not.
The tabulated values of height, h , when the basketball is thrown upward with the initial velocity 79 feet per second, and complete the table given below such that the height as a function of time is represented as h t = − 16 t 2 + 79 t + 5 , t 0 1 2 3 4 5 h Also, from the above table, determine whether the basketball reaches the height of 110 feet or not.
Solution Summary: The author explains how to calculate the height as a function of time when the basketball is thrown upward with the initial velocity 79 feet per second.
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
Chapter 4.2, Problem 78E
( a)
To determine
To calculate:The tabulated values of height, h, when the basketball is thrown upward with the initial velocity 79 feet per second, and complete the table given below such that the height as a function of time is represented as ht=−16t2+79t+5,
t012345h
Also, from the above table, determine whether the basketball reaches the height of 110 feet or not.
( b)
To determine
Whether the ball reaches the height of 110 feet or not, when height, as a function of time, is represented as ht=−16t2+79t+5 for 0≤t≤5.
( c)
To determine
To graph:The function ht=−16t2+48t, and determine graphically whether the ball reaches the height of 110 feet or not.
( d)
To determine
The comparison between the results obtained in part a,b and c, when the height with respect to time function is given as ht=−16t2+79t+5 for 0≤t≤5.
7. From a point 20 m away on a level ground, the angle of elevation to the bottom of a
the top of the window is 32°. Calculate the
window is 27° and the angle of elevatim
height of the window.
(3 marks)
32
SOUCAHTOA
Rom
Coso-Adj
opponite
1270
H
X
Hyp
Tant=OPP
Adj
20 #
Zom
Adjacent
CoS2E 20 XHX Tanz 20
20
K
-0.0445503261 -1.764201788
0-044550326 60044550320
(1 mark) 3960
8. All odd numbers from 1 to 10 are arranged in descending order to form a number.
(i) Write the number.
35798.
97531
31
(ii) Write the total value of the second digit of the number formed in (a) (i)
FA 7X1000-7000
이
(1 mark)
9. A cylinder has a diameter of 28 cm and the height is 18 cm. Calculate its volume.
2
22 × 14 × 14 × 18
-110880m
3
(3 marks)
10. The figure below shows a right pyramid with AB = 3 cm, BC = 5 cm, and AV
VC = VD = 4 cm. Draw its net.
V
3+
12
7/18
(2/20
2105
SSS
20
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