Explanation Given information: The oscillations in air pressure is given by the function is y = 0.02 sin ( 880 π t ) . Graph: The given function is y = 0.02 sin ( 880 π t ) .........(1) To graph the function (1), take the y - axis as the sound pressure and the x - axis as the time that is, t . Since, the graph goes from 0 to 0.01 . So, find the middle values of the interval 0 to 0.01 . To find the middle values of the interval, substitute t = 0.0025 , 0.005 , 0.0075 , 0.01 in the function (1). For t = 0.0025 , substitute 0.0025 for t in the function (1) and simplify. y = 0.02 sin 880 π ( 0.0025 ) = 0.02 sin ( 880 π × 1 400 ) = 0.02 sin 2.2 π = 0.02 × 0.58 = 0.0116 For t = 0.005 , substitute 0.005 for t in the function (1) and simplify. y = 0.02 sin 880 π ( 0.005 ) = 0.02 sin ( 880 π × 1 200 ) = 0.02 sin 4.4 π = 0.02 × 0.95 = 0.019 For t = 0

8th Edition

ISBN: 9781305652224

Author: Charles P. McKeague, Mark D. Turner

Publisher: Cengage Learning

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Chapter 4.2, Problem 66PS

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To graph:

The function y=0.02sin(880πt) for 0≤t≤0.01.

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Chapter 4.2, Problem 65PS

Chapter 4.2, Problem 67PS

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