Generalized Mean Value Theorem Suppose the functions f and g are continuous on ⌈ a, b ⌉ and differentiable on ( a, b ) , where g ( a ) ≠ g ( b ) . Then there is a point c in ( a , b ) at which f ( b ) − f ( a ) g ( b ) − g ( a ) = f ′ ( c ) g ′ ( c ) . This result is known as the Generalized (or Cauchy’s) Mean Value Theorem. a. If g ( x ) = x , then show that the Generalized Mean Value Theorem reduces to the Mean Value Theorem. b. Suppose f ( x ) = x 2 − l, g ( x ) = 4 x + 2, and [ a , b ] = [0, 1]. Find a value of c satisfying the Generalized Mean Value Theorem.
Generalized Mean Value Theorem Suppose the functions f and g are continuous on ⌈ a, b ⌉ and differentiable on ( a, b ) , where g ( a ) ≠ g ( b ) . Then there is a point c in ( a , b ) at which f ( b ) − f ( a ) g ( b ) − g ( a ) = f ′ ( c ) g ′ ( c ) . This result is known as the Generalized (or Cauchy’s) Mean Value Theorem. a. If g ( x ) = x , then show that the Generalized Mean Value Theorem reduces to the Mean Value Theorem. b. Suppose f ( x ) = x 2 − l, g ( x ) = 4 x + 2, and [ a , b ] = [0, 1]. Find a value of c satisfying the Generalized Mean Value Theorem.
Solution Summary: The author explains the Generalized Mean Value Theorem when reduce to the Mean Valuation Theory for the given function. The function is g(x)=x.
Generalized Mean Value Theorem Suppose the functions f and g are continuous on ⌈a, b⌉ and differentiable on (a, b), where g(a) ≠ g(b). Then there is a point c in (a, b) at which
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This result is known as the Generalized (or Cauchy’s) Mean Value Theorem.
a. If g(x) = x, then show that the Generalized Mean Value Theorem reduces to the Mean Value Theorem.
b. Suppose f(x) = x2 − l, g(x) = 4x + 2, and [a, b] = [0, 1]. Find a value of c satisfying the Generalized Mean Value Theorem.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
T
1
7. Fill in the blanks to write the calculus problem that would result in the following integral (do
not evaluate the interval). Draw a graph representing the problem.
So
π/2
2 2πxcosx dx
Find the volume of the solid obtained when the region under the curve
on the interval
is rotated about the
axis.
38,189
5. Draw a detailed graph to and set up, but do not evaluate, an integral for the volume of the
solid obtained by rotating the region bounded by the curve: y = cos²x_for_ |x|
≤
and the curve y
y =
about the line
x =
=플
2
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2
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DG
Find f(x) and g(x) such that h(x) = (fog)(x) and g(x) = 3 - 5x.
h(x) = (3 –5x)3 – 7(3 −5x)2 + 3(3 −5x) – 1
-
-
-
f(x) = ☐
Chapter 4 Solutions
Calculus: Early Transcendentals, Books A La Carte Edition (3rd Edition)
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