Explanation Given: The given function is y = cos θ + sin θ . Calculation: Given: the given interval is [ 0 , 2 π ] . Use sum/ difference rule . ( f + g ) ' = f ' + g ' Now differentiate the function using above rule of derivative. y = cos θ + sin θ y ' = d d θ ( cos θ ) + d d θ ( sin θ ) y ' = − sin θ + cos θ For critical point y ' = 0 . − sin θ + cos θ = 0 ⇒ − sin θ + cos θ + sin θ = sin θ ⇒ cos θ = sin θ ⇒ cos θ cos θ = sin θ cos θ ⇒ 1 = tan θ ⇒ tan θ = 1 θ = π 4 + 2 n π , 5 π 4 + 2 n π Now,

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

21st Edition

ISBN: 9781319438333

Author: Rogawski

Publisher: MAC HIGHER

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Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:

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Question

Chapter 4.2, Problem 52E

To determine

The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 51E

Chapter 4.2, Problem 53E

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Chapter 4 Solutions

ACHIEVE FOR CALCULUS 4 TERM >CSI CUSTOM<

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions