Explanation Given: The given function is y = ( t − t 2 ) 1 3 . Calculation: Given: the given interval is [ − 1 , 2 ] . Apply chain rule. d f ( u ) d x = d f d u ⋅ d u d x y = ( t − t 2 ) 1 3 Let f = u 1 3 , u = ( t − t 2 ) y ' = [ d d u u 1 3 d d t ( t − t 2 ) ] y ' = 1 3 u 2 3 ( 1 − 2 t ) Substitute u = ( t − t 2 ) y ' = 1 3 ( t − t 2 ) 2 3 ( 1 − 2 t ) y ' = ( 1 − 2 t ) 3 ( t − t 2 ) 2 3 For critical point y ' = 0

CALCULUS EARLY TRANSCENDENTALS W/ACHIEVE

4th Edition

ISBN: 9781319057664

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 46E

To determine

Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 45E

Chapter 4.2, Problem 47E

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Chapter 4 Solutions

CALCULUS EARLY TRANSCENDENTALS W/ACHIEVE

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions