Explanation Given: The given function is y = ( t − t 2 ) 1 3 . Calculation: Given: the given interval is [ − 1 , 2 ] . Apply chain rule. d f ( u ) d x = d f d u ⋅ d u d x y = ( t − t 2 ) 1 3 Let f = u 1 3 , u = ( t − t 2 ) y ' = [ d d u u 1 3 d d t ( t − t 2 ) ] y ' = 1 3 u 2 3 ( 1 − 2 t ) Substitute u = ( t − t 2 ) y ' = 1 3 ( t − t 2 ) 2 3 ( 1 − 2 t ) y ' = ( 1 − 2 t ) 3 ( t − t 2 ) 2 3 For critical point y ' = 0

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Question

Chapter 4.2, Problem 46E

To determine

Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 45E

Chapter 4.2, Problem 47E

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Chapter 4 Solutions

Calculus: Early Transcendentals

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions