Explanation Given: The given function is y = ( 2 + x ) 2 + ( 2 − x ) 2 . Calculation: Given: the given interval is [ 0 , 2 ] . Use product rule. ( f ⋅ g ) ' = f ' g + g ' f y = ( 2 + x ) 2 + ( 2 − x ) 2 y ' = d d x ( 2 + x ) ⋅ 2 + ( 2 − x ) 2 + d d x ( 2 + ( 2 − x ) 2 ) ⋅ ( 2 + x ) y ' = 2 + ( 2 − x ) 2 + d d x ( 2 + ( 2 − x ) 2 ) ⋅ ( 2 + x ) Apply chain rule. d f ( u ) d x = d f d u ⋅ d u d x y ' = 2 + ( 2 − x ) 2 + d d x ( 2 + ( 2 − x ) 2 ) ⋅ ( 2 + x ) Let f = u , u = 2 + ( 2 − x ) 2 y ' = 2 + ( 2 − x ) 2 + [ d d u u d d x ( 2 + ( 2 − x ) 2 ) ] ( 2 + x ) y ' = 2 + ( 2 − x ) 2 + [ 1 2 u ⋅ 2 ( 2 − x ) ⋅ − 1 ] ( 2 + x ) Substitute u = 2 + ( 2 − x ) 2 y ' = 2 + ( 2 − x ) 2 + [ ( x − 2 ) 2 + ( 2 − x ) 2 ] ( 2 + x ) y ' = 2 + ( 2<

4th Edition

ISBN: 9781319279813

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 43E

To determine

Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 42E

Chapter 4.2, Problem 44E

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Chapter 4 Solutions

CALCULUS:EARLY TRANS.-SAPLINGPLUS

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions