Explanation Given: The given function is y = 1 − x x 2 + 3 x . Calculation: Given:the given interval is [ 1 , 4 ] . Use quotient rule . ( f g ) ' = f ' ⋅ g − g ' ⋅ f g 2 y = 1 − x x 2 + 3 x y ' = d d x ( 1 − x ) ⋅ ( x 2 + 3 x ) − d d x ( x 2 + 3 x ) ⋅ ( 1 − x ) ( x 2 + 3 x ) 2 y ' = − ( x 2 + 3 x ) − ( 2 x + 3 ) ( 1 − x ) ( x 2 + 3 x ) 2 y ' = − x 2 − 3 x − 2 x − 3 + 2 x 2 + 3 x ( x 2 + 3 x ) 2 y ' = x 2 − 2 x − 3 ( x 2 + 3 x ) 2 For critical point y ' = 0

Loose-leaf Version For Calculus: Early Transcendentals

4th Edition

ISBN: 9781319055912

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Question

Chapter 4.2, Problem 40E

To determine

Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 39E

Chapter 4.2, Problem 41E

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Chapter 4 Solutions

Loose-leaf Version For Calculus: Early Transcendentals

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Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of the given function by comparing with critical and end points.

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Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

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Chapter 4 Solutions