Explanation Given information: Water is flowing at a constant rate (i.e., constant volume per unit time) into a Grecian urn. Calculation: The water is poured ina constant rate then we can say that the volume of the urn is directly proportional to the time. ⇒ V α t ⇒ V = k t w h e r e k i s a c o n s tan t . We know that the width of the urn essentially represents the rate at which the volume increases with respect to height. ⇒ d V d h = c . w ( h ) ⇒ d ( k t ) d h = c

6th Edition

ISBN: 9781119399322

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 4.2, Problem 37P

To determine

To graph:

The depth of the water against time and mark on the graph the time at which the water reaches the widest point of the urn..

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Chapter 4.2, Problem 36P

Chapter 4.2, Problem 38P

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Chapter 4 Solutions

APPLIED CALCULUS (WILEY PLUS)

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To graph: The depth of the water against time and mark on the graph the time at which the water reaches the widest point of the urn..

Solution Summary: The author analyzes the graph of the function t=t(h) with respect to height.