Chapter 4.2, Problem 109E

To determine

(a)

To answer:

If the exponential growth of the deer population is $f\left(x\right)=\mathrm{50,000}{\left(1+0.06\right)}^x$ where 50,000 is the initial deer population and 0.06 is the rate of growth. $f\left(x\right)$ is the total population after x years have passed. Find each value to the nearest thousand.

Predict the total population after 4 yr.

To determine

(b)

To answer:

If the exponential growth of the deer population is $f\left(x\right)=\mathrm{50,000}{\left(1+0.06\right)}^x$ where 50,000 is the initial deer population and 0.06 is the rate of growth. $f\left(x\right)$ is the total population after x years have passed. Find each value to the nearest thousand.

If the initial population was 30, 000 and the growth rate was 0.12, how many deer would be present after 3 yr?

To determine

(c)

To answer:

If the exponential growth of the deer population is $f\left(x\right)=\mathrm{50,000}{\left(1+0.06\right)}^x$ where 50,000 is the initial deer population and 0.06 is the rate of growth. $f\left(x\right)$ is the total population after x years have passed. Find each value to the nearest thousand.

How many additional deer can we expect in 5 yr if the initial population is 45, 000 and the current growth rate is 0.08?