
Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap
8th Edition
ISBN: 9780134581064
Author: Bruice, Paula Yurkanis
Publisher: Prentice Hall
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Question
Chapter 4.13, Problem 48P
Interpretation Introduction
Interpretation:
The identical, enantiomer and diastereomers for the given compound has to be identified from the given structures.
Concept introduction:
Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereo center.
The interchanging the solid-hatched wedge line of two groups of asymmetric centers will give different configuration.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
The pair of Enantiomers non-superimposable mirror images of each other.
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Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
Chapter 4 Solutions
Organic Chemistry; Organic Chemistry Study Guide A Format: Kit/package/shrinkwrap
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