(a) the direction of the electric field vector E → - left-to-right or right-to-left in Fig. 41.15. (b) if the magnitude of field is greater for forward bias or for back bias condition.

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Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

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A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

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Answer 2

Question

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

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Check out a sample textbook solution

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Answer 3

Question

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Answer 6

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Answer 7

Chapter 41, Problem 8Q

To determine

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

Ch. 41 - Prob. 1Q Ch. 41 - Prob. 2Q Ch. 41 - Prob. 3Q Ch. 41 - Prob. 4Q Ch. 41 - Prob. 5Q Ch. 41 - Prob. 6Q Ch. 41 - Prob. 7Q Ch. 41 - Prob. 8Q Ch. 41 - Prob. 9Q Ch. 41 - Prob. 10Q

(a) the direction of the electric field vector E → - left-to-right or right-to-left in Fig. 41.15. (b) if the magnitude of field is greater for forward bias or for back bias condition.

Solution Summary: The author explains how the direction of an electric field vector can be determined by the way a positive test charge may move (or experience force) in the p junction.

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.

Want to see the full answer?

Chapter 41 Solutions

(a) the direction of the electric field vector E → - left-to-right or right-to-left in Fig. 41.15. (b) if the magnitude of field is greater for forward bias or for back bias condition.

Solution Summary: The author explains how the direction of an electric field vector can be determined by the way a positive test charge may move (or experience force) in the p junction.

To find: (a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15. (b) if the magnitude of field is greater for forward bias or for back bias condition.

Want to see the full answer?

Chapter 41 Solutions

To find:

(a) the direction of the electric field vector E→ - left-to-right or right-to-left in Fig. 41.15.

(b) if the magnitude of field is greater for forward bias or for back bias condition.