Explanation Given, s ( t ) = − 16 t 2 + 80 t The above obtained expression is a quadratic expression in ‘ t ’ Comparing with the equation of a quadratic function f ( x ) = a x 2 + b x + c We have, a = − 16 , b = 80 and c = 0 The coefficient of the t 2 term of the obtained expression for s ( t ) is negative. Thus, the graph of the function s ( t ) . Which is a parabola must open downward and its vertex is the highest point. Using the vertex formula, the vertex of the parabola is given by = ( − b 2 a , c − b 2 4 a ) = ( − 80 2 ( − 16 ) , 0 − ( 80 ) 2 4 ( − 16 ) ) = ( − 80 − 32 , − 6400 − 64 ) = ( 2.5 , 100 ) Thus, the time taken to reach maximum height is given by the x -coordinate of the vertex t = 2.5 seconds . s ( t ) = − 16 t 2 + 80 t The object returns to the point from which it was thrown. (i.e.) s ( t ) = 0 Find the x -intercept: s ( t ) = − 16 t 2 + 80 t Substitute s ( t ) = 0 in the above equation

WebAssign with Corequisite Support for Gustafson/Hughes' College Algebra, 12th Edition [Instant Access], Single-Term

12th Edition

ISBN: 9780357422533

Author: Gustafson; R. David; Hughes; Jeff

Publisher: Cengage Learning US

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Chapter 4.1, Problem 86E

To determine

To prove:

That the tossed object took same amount of time for to reach maximum height and to return from that height to the point from which it was thrown.

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Chapter 4.1, Problem 85E

Chapter 4.1, Problem 87E

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To prove: That the tossed object took same amount of time for to reach maximum height and to return from that height to the point from which it was thrown.

Solution Summary: The author explains that the tossed object took the same amount of time for to reach maximum height and to return from that height to the point from which it was thrown.