Fundamentals Of Physics - Volume 1 Only
11th Edition
ISBN: 9781119306856
Author: Halliday
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 41, Problem 3Q
To determine
To find:
the number of atoms per unit cell for silicon.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
10. Imagine you have a system in which you have 54 grams of ice. You can melt this
ice and then vaporize it all at 0 C. The melting and vaporization are done reversibly
into a balloon held at a pressure of 0.250 bar. Here are some facts about water you
may wish to know. The density of liquid water at 0 C is 1 g/cm³. The density of ice at 0
C is 0.917 g/cm³. The enthalpy of vaporization of liquid water is 2.496 kJ/gram and the
enthalpy of fusion of solid water is 333.55 J/gram.
A. How much energy does the ice absorb as heat when it melts?
B. How much work is involved in melting the ice?
C. What is the total change in energy for melting the ice?
D. What is the enthalpy change for melting the ice?
E. What is the entropy change for melting the ice?
F. What is the change in Helmholtz energy for melting the ice?
G. What is the change in Gibbs energy for melting the ice?
In the figure Q = 5.7 nC and all other quantities are accurate to 2 significant figures. What is the magnitude of the force on the charge Q? (k = 1/4πε 0 = 8.99 × 109 N · m2/C2)
Now add a fourth charged particle, particle 3, with positive charge q3, fixed in the yz-plane at (0,d2,d2). What is the net force F→ on particle 0 due solely to this charge? Express your answer (a vector) using k, q0, q3, d2, i^, j^, and k^. Include only the force caused by particle 3.
Chapter 41 Solutions
Fundamentals Of Physics - Volume 1 Only
Ch. 41 - Prob. 1QCh. 41 - Prob. 2QCh. 41 - Prob. 3QCh. 41 - Prob. 4QCh. 41 - Prob. 5QCh. 41 - Prob. 6QCh. 41 - Prob. 7QCh. 41 - Prob. 8QCh. 41 - Prob. 9QCh. 41 - Prob. 10Q
Ch. 41 - Prob. 11QCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5PCh. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 12PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 22PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37PCh. 41 - Prob. 38PCh. 41 - Prob. 39PCh. 41 - Prob. 40PCh. 41 - Prob. 41PCh. 41 - Prob. 42PCh. 41 - Prob. 43PCh. 41 - Prob. 44PCh. 41 - Prob. 45PCh. 41 - Prob. 46PCh. 41 - Prob. 47PCh. 41 - Prob. 48PCh. 41 - Prob. 49PCh. 41 - Prob. 50PCh. 41 - Prob. 51PCh. 41 - Prob. 52PCh. 41 - Prob. 53P
Knowledge Booster
Similar questions
- For a tornadoes and hurricanes, which of the following is most critical? an alert a watch a warning a predictionarrow_forwardWhen a warm front advances up and over a cold front, what is it called? front inversion stationary front cold front occlusion warm front occlusionarrow_forward1) Consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle 1) fixed on the y-axis at (0,d1,0). What is the net force F→ on particle 0 due to particle 1? Express your answer (a vector) using any or all of k, q0, q1, d1, i^, j^, and k^. 2) Now add a third, negatively charged, particle, whose charge is −q2− (particle 2). Particle 2 fixed on the y-axis at position (0,d2,0). What is the new net force on particle 0, from particle 1 and particle 2? Express your answer (a vector) using any or all of k, q0, q1, q2, d1, d2, i^, j^, and k^. 3) Particle 0 experiences a repulsion from particle 1 and an attraction toward particle 2. For certain values of d1 and d2, the repulsion and attraction should balance each other, resulting in no net force. For what ratio d1/d2 is there no net force on particle 0? Express your answer in terms of any or all of the following variables: k, q0, q1, q2.arrow_forward
- A 85 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.35 T field, starting with the normal of the plane of the coil perpendicular to the field. Assume that the positive max emf is reached first. (a) What (in V) is the peak emf? 7.17 V (b) At what time (in s) is the peak emf first reached? 0.196 S (c) At what time (in s) is the emf first at its most negative? 0.589 x s (d) What is the period (in s) of the AC voltage output? 0.785 Sarrow_forwardA bobsled starts at the top of a track as human runners sprint from rest and then jump into the sled. Assume they reach 40 km/h from rest after covering a distance of 50 m over flat ice. a. How much work do they do on themselves and the sled which they are pushing given the fact that there are two men of combined mass 185 kg and the sled with a mass of 200 kg? (If you haven't seen bobsledding, watch youtube to understand better what's going on.) b. After this start, the team races down the track and descends vertically by 200 m. At the finish line the sled crosses with a speed of 55 m/s. How much energy was lost to drag and friction along the way down after the men were in the sled?arrow_forwardFor what type of force is it not possible to define a potential energy expression?arrow_forward
- 10. Imagine you have a system in which you have 54 grams of ice. You can melt this ice and then vaporize it all at 0 C. The melting and vaporization are done reversibly into a balloon held at a pressure of 0.250 bar. Here are some facts about water you may wish to know. The density of liquid water at 0 C is 1 g/cm³. The density of ice at 0 C is 0.917 g/cm³. The enthalpy of vaporization of liquid water is 2.496 kJ/gram and the enthalpy of fusion of solid water is 333.55 J/gram.arrow_forwardConsider 1 mole of supercooled water at -10°C. Calculate the entropy change of the water when the supercooled water freezes at -10°C and 1 atm. Useful data: Cp (ice) = 38 J mol-1 K-1 Cp (water) 75J mol −1 K -1 Afus H (0°C) 6026 J mol −1 Assume Cp (ice) and Cp (water) to be independent of temperature.arrow_forwardThe molar enthalpy of vaporization of benzene at its normal boiling point (80.09°C) is 30.72 kJ/mol. Assuming that AvapH and AvapS stay constant at their values at 80.09°C, calculate the value of AvapG at 75.0°C, 80.09°C, and 85.0°C. Hint: Remember that the liquid and vapor phases will be in equilibrium at the normal boiling point.arrow_forward
- 3. The entropy of an ideal gas is S = Nkg In V. Entropy is a state function rather than a path function, and in this problem, you will show an example of the entropy change for an ideal gas being the same when you go between the same two states by two different pathways. A. Express ASV = S2 (V2) - S₁(V1), the change in entropy upon changing the volume from V₁to V2, at fixed particle number N and energy, U. B. Express ASN = S₂(N₂) - S₁ (N₁), the change in entropy upon changing the particle number from N₁ to N2, at fixed volume V and energy U. C. Write an expression for the entropy change, AS, for a two-step process (V₁, N₁) → (V2, N₁) → (V2, N₂) in which the volume changes first at fixed particle number, then the particle number changes at fixed volume. Again, assume energy is constant.arrow_forwardPlease don't use Chatgpt will upvote and give handwritten solutionarrow_forward6. We used the constant volume heat capacity, Cv, when we talked about thermodynamic cycles. It acts as a proportionality constant between energy and temperature: dU = C₁dT. You can also define a heat capacity for constant pressure processes, Cp. You can think of enthalpy playing a similar role to energy, but for constant pressure processes δαρ C = (37) - Sup Ср ат P = ат Starting from the definition of enthalpy, H = U + PV, find the relationship between Cy and Cp for an ideal gas.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University