The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

Question

The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

Answer 1

Question

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

(e)

To determine

The potential difference when the wavelength goes to zero.

(f)

To determine

The potential difference as the wavelength increases without limit.

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

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Answer 2

Question

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

(e)

To determine

The potential difference when the wavelength goes to zero.

(f)

To determine

The potential difference as the wavelength increases without limit.

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Answer 3

Question

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

(e)

To determine

The potential difference when the wavelength goes to zero.

(f)

To determine

The potential difference as the wavelength increases without limit.

Expert Solution & Answer

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Answer 4

Question

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

(e)

To determine

The potential difference when the wavelength goes to zero.

(f)

To determine

The potential difference as the wavelength increases without limit.

Expert Solution & Answer

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Answer 5

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

(e)

To determine

The potential difference when the wavelength goes to zero.

(f)

To determine

The potential difference as the wavelength increases without limit.

Answer 6

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

Answer 7

Chapter 41, Problem 34P

(a)

To determine

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

Answer 8

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

Answer 9

(b)

To determine

How the required potential to produce x-ray depends on the wavelength of the ray.

Answer 10

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

Answer 11

(c)

To determine

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

Answer 12

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

Answer 13

(d)

To determine

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

Answer 14

(e)

To determine

The potential difference when the wavelength goes to zero.

Answer 15

(e)

To determine

The potential difference when the wavelength goes to zero.

Answer 16

(f)

To determine

The potential difference as the wavelength increases without limit.

Answer 17

(f)

To determine

The potential difference as the wavelength increases without limit.

Answer 18

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Answer 19

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Answer 20

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Answer 29

Ch. 41.3 - Prob. 41.1QQ Ch. 41.3 - Prob. 41.2QQ Ch. 41.4 - Prob. 41.3QQ Ch. 41.4 - Prob. 41.4QQ Ch. 41.8 - Prob. 41.5QQ Ch. 41 - Prob. 1P Ch. 41 - Prob. 2P Ch. 41 - Prob. 3P Ch. 41 - Prob. 4P Ch. 41 - Prob. 5P

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

Solution Summary: The author explains the minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

Concept explainers

The minimum potential difference through which the electrons needed to be accelerated to produce x-ray.

How the required potential to produce x-ray depends on the wavelength of the ray.

To explain whether the result in the previous sections predicts the correct minimum wavelength in Figure 41.22.

Whether the relation found in section (a) is equally applicable to other kinds of electromagnetic radiations.

The potential difference when the wavelength goes to zero.

The potential difference as the wavelength increases without limit.

Chapter 41 Solutions