MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
5th Edition
ISBN: 9780135472460
Author: REGES, Stuart, Stepp, Marty
Publisher: PEARSON
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Chapter 4.1, Problem 1SCP

Explanation of Solution

Improving the performance:

a)

  • z is odd:
  • The logical test version of the above given English statement is: z%2==1
  • The logic for the even number is z%2==0 which means the given logic is for the odd numbers.

b)

  • z is not greater than y’s square root:
  • The logical test version of the above given English statement is: z <= Math.sqrt(y).
  • If z is not greater than y’ square root, then the possibilities are that it may be lesser than or equal to y; square root.

c)

  • y is positive:
  • The logical test version of the above given English statement is: y > 0
  • The numbers greater than zero are considered to be positive numbers.

d)

  • Either x or y is even, and the other is odd:
  • The logical test version of the above given English statement is: x % 2 != y % 2.
  • If x%2 results zero then y%2 should result as one, which means both of the results cannot be the same.

e)

  • y is a multiple of z:
  • The logical test version of the above given English statement is: y % z == 0.
  • If y mod z which is y%z results zero, then z is known to be the factor of y.

f)

  • z is not zero:
  • The logical test version of the above given English statement is: z != 0
  • “!=” implies not equal to which means z is not equal to zero...

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Can you help me solve this problem using Master's Theorem:Solve the recurrence relation f(n) = 3af(n/a) + (n + a)2 with f(1) = 1 and a > 1 byfinding an expression for f(n) in big-Oh notation.
here is example 7.6## Example 7.6 Suppose the sample population is χ 2 (2), which is non-normal but with same variance 4. ▶ Repeat the simulation, but replacing the N(0, 4) samples with χ 2 (2) samples. ▶ Calculate the empirical confidence level.(Empirical confidence level) n <- 20 alpha <- 0.05 UCL <- replicate(1000, expr = { x <- rchisq(n,df=2) (n-1)*var(x)/qchisq(alpha,df=n-1) }) sum(UCL >4) mean(UCL > 4) ## t.test function n <- 20 x <- rnorm(n,mean=2) result <- t.test(x,mu=1) result$statistic result$parameter result$p.value result$conf.int result$estimate
using r language

Chapter 4 Solutions

MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs

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