EBK ELECTRIC MOTOR CONTROL
EBK ELECTRIC MOTOR CONTROL
10th Edition
ISBN: 9780100784598
Author: Herman
Publisher: YUZU
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Chapter 40, Problem 9SQ
To determine

Explain the reason for the operation of field contacts (F) overlapped in Figure 40-1.

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9-3) similar to Lathi & Ding, Prob. P.5.2-3 In a satellite radio system, 200 stereo stations are to be packaged in one data stream. For each station, two (left & right) signals of bandwidth 22 kHz are sampled, quantized, and binary-coded into PCM signals. The transmitter then multiplexes the data from the 200 stations into a single stream via TDM and modulates that stream onto a radio carrier using DSB-SC-AM. (a) If the maximum acceptable quantization error is 0.25% of the peak signal voltage, find the minimum number of bits needed for a uniform quantizer. (b) If the sampling rate must be 25% higher than the Nyquist rate, find the minimum bit rate of the multiplexed data stream, based on the quantizer of part (a). (c) If 10% more bits are added for error correction and framing, determine the minimum bandwidth of the radio signal sent to the ground receivers.
9-2) similar to Lathi & Ding, Prob. P.5.2-1 A compact disc (CD) records audio signals digitally by using PCM. Assume that the audio signal bandwidth equals 15 kHz. (a) If the Nyquist samples are uniformly quantized into L = 65, 536 levels and then binary-coded, determine the number of binary digits required to encode a sample. (b) if the audio signal has a peak voltage of ±1V and an average signal power of 0.1 V2, find the resulting ratio of signal to quantization noise (SQNR) for the system. (c) Determine the number of binary digits per second (bit/s) required to encode the audio signal. (d) For practical reasons discussed in the text, signals are sampled at a rate well above the Nyquist rate. Practical CDs use 44,100 samples per second. If L = 65,536, determine the number of bits per second required to encode the signal and the minimum bandwidth required to transmit the encoded signal.
12.1 Evaluate each of the following integrals: (a) G₁ =√(31³ −4t²+3)[8(t) +28(t − 2)] dt. (b) G2=2(e³t +1)[8(t) −28(t − 2)] dt. 16 (c) G3 = √124t sin(2лt) − 1][§(t − 1)+8(t −6)] dt.|
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