Explanation Given information: The provided expression is ( 3 y 5 − y 2 + 12 y ) ÷ ( 3 y ) . Formula used: The quotient rule for any arbitrary number x and positive integers p and q along with the condition p > q is: x p x q = x p − q The distributive rule, for any arbitrary numbers a, b, and c is a ( b + c ) = a ⋅ b + a ⋅ c . Calculation: Consider the provided expression, ( 3 y 5 − y 2 + 12 y ) ÷ ( 3 y ) Rewrite the expression as, ( 3 y 5 − y 2 + 12 y ) ( 3 y ) Separate out the terms and coefficients, ( 3 y 5 − y 2 + 12 y ) ( 3 y ) = 3 y 5 3 y − y 2 3 y + 12 y 3 y = 3 3 ⋅ y 5 y − 1 3 ⋅ y 2 y + 12 3 ⋅ y y = y 5 y − 1 3 ⋅ y 2 y + 4 ⋅ y y Apply the formula, the quotient rule for any arbitrary number x and positive integers p and q along with the condition p > q is: x p x q = x

6th Edition

ISBN: 9780321848741

Author: Marvin L. Bittinger

Publisher: PEARSON

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Chapter 4, Problem 70RE

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To calculate: The value of the division of the expression (3y5−y2+12y)÷(3y).

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Chapter 4, Problem 69RE

Chapter 4, Problem 71RE

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The value of the division of the expression ( 3 y 5 − y 2 + 12 y ) ÷ ( 3 y ) .

Solution Summary: The author explains the quotient rule for any arbitrary number x and positive integers p and q along with the distributive rule.

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To calculate: The value of the division of the expression (3y5−y2+12y)÷(3y).

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Chapter 4 Solutions