Chapter 4, Problem 66RE

K 7 Use the fact that the derivative of the function f(x) == is f'(x)= x = -9. (x) = -7/₁ to find the equation of the tangent line to the graph of f(x) at the point The equation of the tangent line to the graph of f(x) at the point x = -9 is.

Implicit Differentiation The equation for the curve graphed to the left is x3 - y3 – 6xy = 0. Keep in mind that y is a function of x. When we take the derivative of y we need to use the chain rule because y depends on x: it may help to write it as Use implicit differentiation to find in terms of the -4 -2 variables x and y.

A function has the derivative f'(x) = 3x2 - 7x + 2. What are the stationary points of f, and their natures. Help fill in the blanks.  The x-coordinate of one stationary point is at x = ____. It is a _____. (local maximum, local minimum or horizontal point of inflection).  The x-coordinate of the other stationary point is at x = ____. It is a ____. (local maximum, local minimum or horizontal point of inflection).