Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th
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Chapter 4, Problem 55E
Interpretation Introduction

Interpretation:

The mass of CO2 is to be determined for different amounts of methane.

Concept introduction:

The characteristic mass of a compound is the formula mass of the compound, which is obtained by adding the atomic masses of all atoms.

A conversion factor is a numerical ratio, which is used to change one unit into another.

The chemical formula represents the precise number of atoms in a molecule, but not their structural arrangement.

Expert Solution & Answer
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Answer to Problem 55E

Solution: The masses of CO2 for different amounts of methane are given as follows:

1.0×102g CO2

23g CO2

30g CO2

3.6×103g CO2

Explanation of Solution

a) 2.3mol CH4

The equivalence is obtained between moles of CH4 and moles CO2 with the help of the chemical formula as follows:

1mol CO21mol CH4

The equivalence is obtained between grams of CO2 and moles of CO2 with the help of the chemical formula as follows:

1mol CO244g CO2

In order to obtain the mass of CO2, the conversion factor proceeds as follows:

2.3mol CH4×(1mol CO21mol CH4)×(44g CO21mol CO2)=1.0×102g CO2

Here,

molarmass of CO2=44g/mol

Therefore, the amount of CO2 is 1.0×102 g.

b) 0.52mol CH4

The equivalence is obtained between moles of CH4 and moles of CO2 with the help of the chemical formula as follows:

1mol CO21mol CH4

The equivalence is obtained between grams of CO2 and moles of CO2 with the help of the chemical formula as follows:

1mol CO244g CO2

In order to obtain the mass of CO2, the conversion factor proceeds as follows:

0.52mol CH4×(1mol CO21mol CH4)×(44g CO21mol CO2)=23g CO2

molarmass of CO2=44g/mol

Therefore, the amount of CO2 is 23g

c) 11g CH4

The equivalence is obtained between grams of CH4 and moles of CH4 with the help of the chemical formula as follows:

1mol CH416g CH4

The equivalence is obtained between moles of CH4 and moles of CO2 with the help of the chemical formula as follows:

1mol CO21mol CO2

The equivalence is obtained between grams of CO2 and moles of CO2 with the help of the chemical formula as follows:

1mol CO244g CO2

In order to obtain the mass of CO2, the conversion factor proceeds as follows:

11g CH4×(1mol CH416g CH4)×(1mol CO21mol CH4)×(44g CO21mol CO2)=30g CO2

Here,

molarmass of CH4=16g/mol

molarmass of CO2=44g/mol

Therefore, the amount of CO2 is 30 g.

d) 1.3kg CH4

The equivalence is obtained between grams of CH4 and moles of CH4 with the help of the chemical formula as follows:

1mol CH416g CH4

The equivalence is obtained between moles of CH4 and moles of CO2 with the help of the chemical formula as follows:

1mol CO21mol CO2

The equivalence is obtained between grams of CO2 and moles of CO2 with the help of the chemical formula as follows:

1mol CO244g CO2

In order to obtain the mass of CO2, the conversion factor proceeds as follows:

1.3kg CH4×(1000g1kg)×(1mol CH416g CH4)×(1mol CO21mol CH4)×(44g CO21mol CO2)=3.6×103g CO2

Here,

molarmass of CH4=16g/mol

molarmass of CO2=44g/mol

Therefore, the amount of CO2 is 3.6×103 g.

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Chapter 4 Solutions

Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th

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