PHYSICAL CHEMISTRY-WEBASSIGN
11th Edition
ISBN: 9780357087411
Author: ATKINS
Publisher: CENGAGE L
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Question
Chapter 4, Problem 4B.8BE
(i)
Interpretation Introduction
Interpretation: The enthalpy of vaporization of a liquid has to be calculated.
Concept introduction: Energy needed to transform the liquid state of a substance to its gaseous state is known as the enthalpy of vaporization of the system. Enthalpy of vaporization of a system can be calculated by the Clausius-Clapeyron’s expression.
(ii)
Interpretation Introduction
Interpretation: The normal boiling point of a liquid has to be calculated.
Concept introduction: Energy needed to transform the liquid state of a substance to its gaseous state is known as the enthalpy of vaporization of the system. Enthalpy of vaporization of a system can be calculated by the Clausius-Clapeyron’s expression.
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Question 59 of 70
The volume of
1
unit of plasma is 200.0 mL
If the recommended dosage
for adult patients is 10.0 mL per kg of body mass, how many units are needed for
a patient with a body mass of 80.0
kg ?
80.0
kg
10.0
DAL
1
units
X
X
4.00
units
1
1
Jeg
200.0
DAL
L
1 units
X
200.0 mL
= 4.00 units
ADD FACTOR
*( )
DELETE
ANSWER
RESET
D
200.0
2.00
1.60 × 10³
80.0
4.00
0.0400
0.250
10.0
8.00
&
mL
mL/kg
kg
units/mL
L
unit
Q Search
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111
110
19
Identify the starting material in the following reaction. Click the "draw structure" button to launch the
drawing utility.
draw structure ...
[1] 0 3
C10H18
[2] CH3SCH3
H
In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that
PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C.
2 NH3 (g) N2 (g) + 3 H₂ (g)
K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104
Chapter 4 Solutions
PHYSICAL CHEMISTRY-WEBASSIGN
Ch. 4 - Prob. 4B.1STCh. 4 - Prob. 4B.2STCh. 4 - Prob. 4A.1DQCh. 4 - Prob. 4A.2DQCh. 4 - Prob. 4A.3DQCh. 4 - Prob. 4A.1AECh. 4 - Prob. 4A.1BECh. 4 - Prob. 4A.2AECh. 4 - Prob. 4A.2BECh. 4 - Prob. 4A.3AE
Ch. 4 - Prob. 4A.3BECh. 4 - Prob. 4A.4AECh. 4 - Prob. 4A.4BECh. 4 - Prob. 4A.5AECh. 4 - Prob. 4A.5BECh. 4 - Prob. 4A.1PCh. 4 - Prob. 4A.2PCh. 4 - Prob. 4A.3PCh. 4 - Prob. 4A.4PCh. 4 - Prob. 4B.1DQCh. 4 - Prob. 4B.2DQCh. 4 - Prob. 4B.3DQCh. 4 - Prob. 4B.1AECh. 4 - Prob. 4B.1BECh. 4 - Prob. 4B.2AECh. 4 - Prob. 4B.2BECh. 4 - Prob. 4B.3AECh. 4 - Prob. 4B.3BECh. 4 - Prob. 4B.4AECh. 4 - Prob. 4B.4BECh. 4 - Prob. 4B.5AECh. 4 - Prob. 4B.5BECh. 4 - Prob. 4B.6AECh. 4 - Prob. 4B.6BECh. 4 - Prob. 4B.7AECh. 4 - Prob. 4B.7BECh. 4 - Prob. 4B.8AECh. 4 - Prob. 4B.8BECh. 4 - Prob. 4B.9AECh. 4 - Prob. 4B.9BECh. 4 - Prob. 4B.10AECh. 4 - Prob. 4B.10BECh. 4 - Prob. 4B.11AECh. 4 - Prob. 4B.11BECh. 4 - Prob. 4B.12AECh. 4 - Prob. 4B.12BECh. 4 - Prob. 4B.13AECh. 4 - Prob. 4B.13BECh. 4 - Prob. 4B.14AECh. 4 - Prob. 4B.14BECh. 4 - Prob. 4B.1PCh. 4 - Prob. 4B.2PCh. 4 - Prob. 4B.3PCh. 4 - Prob. 4B.4PCh. 4 - Prob. 4B.5PCh. 4 - Prob. 4B.6PCh. 4 - Prob. 4B.7PCh. 4 - Prob. 4B.8PCh. 4 - Prob. 4B.9PCh. 4 - Prob. 4B.10PCh. 4 - Prob. 4B.11PCh. 4 - Prob. 4B.12PCh. 4 - Prob. 4B.13PCh. 4 - Prob. 4B.14PCh. 4 - Prob. 4B.15PCh. 4 - Prob. 4B.16PCh. 4 - Prob. 4.1IACh. 4 - Prob. 4.3IACh. 4 - Prob. 4.4IA
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY