Concept explainers
(a)
Interpretation:
Lone pairs should be added where needed and the total number of valence electrons in glycine should be counted.
Concept Introduction:
Valence electrons are the electrons reside in valence shell of an atom and valence electrons are the ones which participate in bonding. In main group elements, group number equals to the number of valence electrons. The sum gives the total number of valence electrons in a molecule.
(b)
Interpretation:
The shape around the four indicated atoms should be determined.
Concept Introduction:
To determine the shape around a given
(c)
Interpretation:
All polar bonds in glycine should be labeled.
Concept Introduction:
The electronegativity difference can be used to differentiate bonds as polar, polar covalent and ionic bonds in different compounds.
If the electronegativity difference between two atoms is less than 0.5, the bond is nonpolar in which electrons are equally shared. If the electronegativity difference is between 0.5 − 1.9, the bond is polar covalent, in which electrons are unequally shared, the electron density is more towards electronegative atom. For electronegativity difference more than 1.9, the bond is ionic, in which electrons has been transferred from the less electronegative atom to more electronegative atom.
(e)
Interpretation:
Whether the glycine is a polar molecule should be determined.
Concept Introduction:
Polarity of a molecule depends on the individual bonds and the overall shape. If a molecule has no polar bonds, then the molecule is nonpolar. If the molecule has one polar bond, then the molecule is considered to be polar. If a molecule has more than one polar bond, the shape of the molecule determines the polarity of the molecule. If the bond dipoles do not cancel, the molecule is polar. If they get cancelled, the molecule is non-polar.

Want to see the full answer?
Check out a sample textbook solution
Chapter 4 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
- 18:57 .III LTE www-awu.aleks.com Chapter 12 HW Question 31 of 39 (8 points) | Question Attem... Give the IUPAC name of each compound. Part 1 of 4 Part 2 of 4 Х Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS OF US vacy Center | Accessibilityarrow_forwardWhat is the missing reactant in this organic reaction? CH3-C-CH2-NH2 + R - CH3 O: 0 CH3-N-CH2-C-NH-CH2-C-CH3 + H2O Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. Explanation Check Click anywhere to draw the first atom of your structure. C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardDone 18:17 • www-awu.aleks.com Chapter 12 HW Question 24 of 39 (4 points) | Question Attempt: 1 of Unlimited ▼ 20 ✓ 21 × 22 23 24 25 26 raw the structure corresponding to each IUPAC name. Part 1 of 2 .III LTE 22 27 28 סוי 29 29 3 A skeletal structure corresponding to the IUPAC name 3-ethyl-4-methylhexane. Part 2 of 2 Click and drag to start drawing a structure. A condensed structure corresponding to the IUPAC name 2,2,4- trimethylpentane. Click anywhere to draw the first atom of your structure. Check Save For Later Submit < Х ப: G © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility : Garrow_forward
- Done 18:25 www-awu.aleks.com .III LTE Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimi... Oli 23 24 25 26 27 28 29 30 Consider this structure. CH2 CH2CH2 CH2CH2CH₂ C -C. -CH2CH3 H CH Part: 0 / 3 Part 1 of 3 Give the IUPAC name of this structure. Skip Part < Check ☑ Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility ....................arrow_forwardCalculate Ecell at 25.0 oC using the following line notation. Zn(s)|Zn+2(aq, 0.900 M)||Cu+2(aq, 0.000200 M)|Cu(s)arrow_forwardPredict the product of this organic reaction: O OH + H + OH A P + H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there isn't any P because this reaction won't happen, check the No reaction box under the drawing area. Explanation Check Click and drag to start drawing a structure. X G ☐ :arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHER
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning



