
In Problems 47-50 use systematic elimination to solve the given system.
47.

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Chapter 4 Solutions
FIRST CRSE.IN DIFF.EQUAT..-ACCESS
- Question 3 Rewrite 4 = log₂(16) in exponential form. Question 4 症 If log, (6x+3)= 4, then rarrow_forwardQuestion 6 Find the solution of the exponential equation 2t 100(1.07) 2 = 500,000 in terms of logarithms, or correct to four decimal places. t=arrow_forwardQuestion 6 Find the solution of the exponential equation 100(1.07)² = 500, 000 in terms of logarithms, or correct to four decimal places. t = Question 7 Solve the equation.arrow_forward
- 18. Let X be normally distributed with mean μ = 2,500 and stan- dard deviation σ = 800. a. Find x such that P(X ≤ x) = 0.9382. b. Find x such that P(X>x) = 0.025. ة نفـة C. Find x such that P(2500arrow_forward17. Let X be normally distributed with mean μ = 2.5 and standard deviation σ = 2. a. Find P(X> 7.6). b. Find P(7.4≤x≤ 10.6). 21 C. Find x such that P(X>x) = 0.025. d. Find x such that P(X ≤x≤2.5)= 0.4943. and stan-arrow_forward(1) Let M and N be non-empty subsets of a linear space X, show that whether = U or not, and show that there whether exsits a liear function from P₂(x) into R' which onto but not one-to-one or not. ام (2) Let R be a field of real numbers and P,(x)=(a+bx+cx? / a,b,ce R} be a vector space over R, show that whether there exsit two hyperspaces A and B such that AUB is a hyperspace or not. (3) Let A be an affine set in a linear space X over afield F and tEA, show that A-t is a subspace of Xand show that if M and N are balanced sets then M+N is balanced set. (4) Write the definition of bounded set in a normed space, and write with prove an equivalent statement to definition. (5) Let d be a metric on a linear space X over a field F, write conditions on d in order to get that there is a norm on X induced dy d and prove that. (6) Let M be a non-empty subset of a normed space X, show that xEcl(M) iff for any r>o there exsits yEM such that llx-yllarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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