Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
2nd Edition
ISBN: 9780077633707
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
Question
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Chapter 4, Problem 4.60AP

(a)

Interpretation Introduction

Interpretation:

The compound, which exhibits weaker intermolecular forces, has to be given.

Concept introduction:

London Dispersion forces:

London dispersion forces are weak interactions due to the temporary changes in electron density in a molecule.  All covalent compound exhibits London dispersion forces.  These intermolecular forces are the only intermolecular forces present in nonpolar compounds.

Hydrogen Bonding:

A chemical bond in which a hydrogen atom of one molecule is attracted to an electronegative atom especially a nitrogen, oxygen, or fluorine atom, usually of another molecule.

Dipole-dipole interactions:

Dipole–dipole interactions are electrostatic interactions between molecules which have permanent dipoles. This interaction is stronger than the London forces but is weaker than ion-ion interaction because only partial charges are involved positive end of a polar molecule will attract the negative end of the other molecule and influence its position

(b)

Interpretation Introduction

Interpretation:

The compound that has lower boiling point has to be given.

(c)

Interpretation Introduction

Interpretation:

The compound that has lower melting point has to be given.

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What is the strongest intermolecular force present in 2-methylbutane, (CH3)2CHCH2CH3 ? a. Dipole-dipole forces b. Hydrogen bonding c. London forces d. Ionic bonding
Macmillan Learning A: the chemical formulas for the two compounds. OH A B: Based on their structures, which compound will have the higher boiling point? B
a. Which substance, CH3 CH₂OH or CH3 CH₂ CH₂OH, would be expected to have a lower boiling point? Why? CH3 CH₂OH, because it has a stronger OH group. CH3 CH₂ CH₂OH, because it has stronger London forces. CH3 CH₂OH, because it has a smaller molar mass. CH3 CH₂ CH₂OH, because it has a larger molar mass. b. Which substance, CH4 or CH3OH, would be expected to have a lower boiling point? Why? OCH4, because only London forces are operating. OCH3OH, because it is capable of hydrogen bonding. CH4, because it is capable of hydrogen bonding. OCH, OH, because it has larger molar mass. c. Which substance, CH3 CH₂ CH2OH or CH3 CH₂ CH₂ CH₂ CH3, would be expected to have a lower boiling point? Why? CH3 CH₂ CH₂OH, because it is capable of hydrogen bonding. CH3 CH₂ CH₂ CH2 CH3, because it is not capable of hydrogen bonding. CH3 CH₂ CH₂OH, because it has a larger molar mass. CH3 CH₂ CH₂ CH₂ CH3, because it has a smaller molar mass.

Chapter 4 Solutions

Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry

Ch. 4.3 - Which of the compounds in each pair has stronger...Ch. 4.4 - Prob. 4.12PCh. 4.4 - Prob. 4.13PCh. 4.5 - A student has two containers one with 10 g of...Ch. 4.5 - Prob. 4.15PCh. 4.5 - How much energy is required to heat 28.0 g of iron...Ch. 4.5 - Prob. 4.17PCh. 4.5 - Prob. 4.18PCh. 4.5 - Prob. 4.19PCh. 4.6 - Prob. 4.20PCh. 4.6 - Prob. 4.21PCh. 4.6 - Label each process as endothermic or exothermic...Ch. 4.6 - Prob. 4.23PCh. 4.7 - Answer the following questions about the graph. a....Ch. 4.7 - Prob. 4.25PCh. 4.7 - If the cooling curve in Figure 4.5 represented a...Ch. 4.7 - How much energy (in calories) is released when...Ch. 4.7 - Prob. 4.28PCh. 4 - What phase change is shown in the accompanying...Ch. 4 - What phase change is shown in the accompanying...Ch. 4 - Consider the cooling curve drawn below. a. Which...Ch. 4 - Which line segments on the cooling curve in...Ch. 4 - Prob. 4.33UKCCh. 4 - Prob. 4.34UKCCh. 4 - Prob. 4.35UKCCh. 4 - Prob. 4.36UKCCh. 4 - Prob. 4.37UKCCh. 4 - Prob. 4.38UKCCh. 4 - Prob. 4.39APCh. 4 - Prob. 4.40APCh. 4 - Prob. 4.41APCh. 4 - Prob. 4.49APCh. 4 - Prob. 4.50APCh. 4 - Prob. 4.54APCh. 4 - Prob. 4.55APCh. 4 - Prob. 4.56APCh. 4 - Prob. 4.57APCh. 4 - Prob. 4.58APCh. 4 - Prob. 4.59APCh. 4 - Prob. 4.60APCh. 4 - Prob. 4.61APCh. 4 - Prob. 4.62APCh. 4 - Prob. 4.63APCh. 4 - Prob. 4.64APCh. 4 - Prob. 4.65APCh. 4 - Prob. 4.66APCh. 4 - Prob. 4.67APCh. 4 - Prob. 4.68APCh. 4 - Prob. 4.69APCh. 4 - Prob. 4.70APCh. 4 - Prob. 4.71APCh. 4 - Prob. 4.72APCh. 4 - Prob. 4.73APCh. 4 - Prob. 4.74APCh. 4 - Prob. 4.75APCh. 4 - Prob. 4.76APCh. 4 - Prob. 4.77APCh. 4 - Prob. 4.78APCh. 4 - Prob. 4.79APCh. 4 - Why does steam form when hot lava falls into the...Ch. 4 - Prob. 4.81APCh. 4 - Prob. 4.82AP
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