Explanation During a drag-race, the vehicle exerts a very strong force on the ground. This in turn exerts a very large acceleration on the vehicle. The force of kinetic friction between the tires and the surface provides the acceleration for the vehicle. Given: The distance covered by the drag-racer s = 1 km = 1000 m The time taken to cover the distance t = 12 s The initial speed of the drag-racer is v 0 = 0 Formula used: Frictional force can be obtained by: F f r = μ k F N According to Newton’s second law of motion: F f r = m a Second equation of motion is: s = v 0 t + 1 2 a t 2 Here, the force of kinetic friction is F f r , acceleration due to gravity is g , the mass of the car is m , its acceleration is a , initial speed is v 0 , its final speed is v and the time taken to travel this distance is t . The weight W of the car acts vertically downwards and due to Newton’s third law, the car experiences an upward force called normal force F N .Since, there is no motion either in the upward and the downward directions, F N + W = 0 Therefore, F N = − W The normal force has the same magnitude as that of the weight and it acts opposite to the direction of the weight. As the magnitude of the normal force is F N = m g . The force of kinetic friction is related to the normal force as, F f r = μ k F N Therefore F f r = μ k m g

7th Edition

ISBN: 9780321625915

Author: Douglas C. Giancoli

Publisher: PEARSON

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Chapter 4, Problem 45P

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The coefficient of kinetic friction between the drag-race tires in contact with an asphalt surface.

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Chapter 4, Problem 44P

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