Principles of General Organic & Biological Chemistry
Principles of General Organic & Biological Chemistry
2nd Edition
ISBN: 9780077633721
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
Question
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Chapter 4, Problem 4.59AP

(a)

Interpretation Introduction

Interpretation:

The compound that exhibits weaker intermolecular forces has to be given.

Concept introduction:

London Dispersion forces:

London dispersion forces are weak interactions due to the temporary changes in electron density in a molecule.  All covalent compound exhibits London dispersion forces.  These intermolecular forces are the only intermolecular forces present in nonpolar compounds.

Hydrogen Bonding:

A chemical bond in which a hydrogen atom of one molecule is attracted to an electronegative atom especially a nitrogen, oxygen, or fluorine atom, usually of another molecule.

Dipole-dipole interactions:

Dipole–dipole interactions are electrostatic interactions between molecules which have permanent dipoles. This interaction is stronger than the London forces but is weaker than ion-ion interaction because only partial charges are involved positive end of a polar molecule will attract the negative end of the other molecule and influence its position

(b)

Interpretation Introduction

Interpretation:

The compound, which has higher boiling point, has to be given.

(c)

Interpretation Introduction

Interpretation:

The compound, which has higher melting point, has to be given.

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Chapter 4 Solutions

Principles of General Organic & Biological Chemistry

Ch. 4.3 - Which of the compounds in each pair has stronger...Ch. 4.4 - Prob. 4.12PCh. 4.4 - Prob. 4.13PCh. 4.5 - A student has two containers one with 10 g of...Ch. 4.5 - Prob. 4.15PCh. 4.5 - How much energy is required to heat 28.0 g of iron...Ch. 4.5 - Prob. 4.17PCh. 4.5 - Prob. 4.18PCh. 4.5 - Prob. 4.19PCh. 4.6 - Prob. 4.20PCh. 4.6 - Prob. 4.21PCh. 4.6 - Label each process as endothermic or exothermic...Ch. 4.6 - Prob. 4.23PCh. 4.7 - Answer the following questions about the graph. a....Ch. 4.7 - Prob. 4.25PCh. 4.7 - If the cooling curve in Figure 4.5 represented a...Ch. 4.7 - How much energy (in calories) is released when...Ch. 4.7 - Prob. 4.28PCh. 4 - What phase change is shown in the accompanying...Ch. 4 - What phase change is shown in the accompanying...Ch. 4 - Consider the cooling curve drawn below. a. Which...Ch. 4 - Which line segments on the cooling curve in...Ch. 4 - Prob. 4.33UKCCh. 4 - Prob. 4.34UKCCh. 4 - Prob. 4.35UKCCh. 4 - Prob. 4.36UKCCh. 4 - Prob. 4.37UKCCh. 4 - Prob. 4.38UKCCh. 4 - Prob. 4.39APCh. 4 - Prob. 4.40APCh. 4 - Prob. 4.41APCh. 4 - Prob. 4.49APCh. 4 - Prob. 4.50APCh. 4 - Prob. 4.54APCh. 4 - Prob. 4.55APCh. 4 - Prob. 4.56APCh. 4 - Prob. 4.57APCh. 4 - Prob. 4.58APCh. 4 - Prob. 4.59APCh. 4 - Prob. 4.60APCh. 4 - Prob. 4.61APCh. 4 - Prob. 4.62APCh. 4 - Prob. 4.63APCh. 4 - Prob. 4.64APCh. 4 - Prob. 4.65APCh. 4 - Prob. 4.66APCh. 4 - Prob. 4.67APCh. 4 - Prob. 4.68APCh. 4 - Prob. 4.69APCh. 4 - Prob. 4.70APCh. 4 - Prob. 4.71APCh. 4 - Prob. 4.72APCh. 4 - Prob. 4.73APCh. 4 - Prob. 4.74APCh. 4 - Prob. 4.75APCh. 4 - Prob. 4.76APCh. 4 - Prob. 4.77APCh. 4 - Prob. 4.78APCh. 4 - Prob. 4.79APCh. 4 - Why does steam form when hot lava falls into the...Ch. 4 - Prob. 4.81APCh. 4 - Prob. 4.82AP
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