SCIENCE+ENGR.OF MTRLS.,SI ED.,ENHANCED
7th Edition
ISBN: 9780357447888
Author: ASKELAND
Publisher: CENGAGE L
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Chapter 4, Problem 4.52P
To determine
The ASTM grain size number
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Hints: Find the closed loop transfer function and then plot the step response for diFerentvalues of K in MATLAB. Show step response plot for different values of K.
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37. The vertical shaft shown in Figure P12-37 is driven at a
speed of 600 rpm with 4.0 hp entering through the bevel
gear. Each of the two chain sprockets delivers 2.0 hp to
the side to drive mixer blades in a chemical reactor vessel.
The bevel gear has a diametral pitch of 5, a pitch diameter
of 9.000 in, a face width of 1.31 in, and a pressure angle
of 20°. Use SAE 4140 OQT 1000 steel for the shaft. See
Chapter 10 for the methods for computing the forces on
the bevel gear.
Figure P12-37: P37-Bevel gear drive with two chain
sprockets
Each problem includes the following details:
■Design the complete shaft, including the specification of
the overall geometry and the consideration of stress con-
centration factors. The analysis would show the minimum
acceptable diameter at each point on the shaft to be safe
from the standpoint of strength.
Homework Problems 12-24, 12-35, and 12-37 from
textbook, done in spreadsheet form. Place drawings of the
load, shear, and bending moment body diagrams…
35. The double-reduction, helical gear reducer shown in
Figure P12-35 transmits 5.0 hp. Shaft 1 is the input,
rotating at 1800 rpm and receiving power directly from an
electric motor through a flexible coupling. Shaft 2 rotates
at 900 rpm. Shaft 3 is the output, rotating at 300 rpm. A
chain sprocket is mounted on the output shaft as shown
and delivers the power upward. The data for the gears
are given in Table 12-5. Each gear has a 1412° normal
pressure angle and a 45° helix angle. The combinations of
left- and right-hand helixes are arranged so that the axial
forces oppose each other on shaft 2 as shown. Use SAE
4140 OQT 1200 for the shafts.
Figure P12-35: P35-Double-reduction helical drive
Each problem includes the following details:
■Design the complete shaft, including the specification of
the overall geometry and the consideration of stress con-
centration factors. The analysis would show the minimum
acceptable diameter at each point on the shaft to be safe
from the standpoint of…
Chapter 4 Solutions
SCIENCE+ENGR.OF MTRLS.,SI ED.,ENHANCED
Ch. 4 - Gold has 5.82108vacancies/cm3 at equilibrium at...Ch. 4 - Prob. 4.2PCh. 4 - Calculate the number of vacancies per cm3 expected...Ch. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Au and Ag form a substitutional solid solution....
Ch. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Write down the defect chemistry equation for...Ch. 4 - Prob. 4.20PCh. 4 - What is the Burger’s vector orientation...Ch. 4 - What is slip system and what role does it play in...Ch. 4 - Draw a Burgers circuit around the dislocation...Ch. 4 - What are the Miller indices of the slip...Ch. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Calculate the length of the Burgers vector in the...Ch. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - The crystal shown in Figure 4-19 contains two...Ch. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Why is it that single crystal and polycryst alline...Ch. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Determine the ASTM grain size number for the...Ch. 4 - Certain ceramics with special dielectric...Ch. 4 - Prob. 4.61PCh. 4 - Calculate the angle of a smalla ngle grain...Ch. 4 - For BCC iron, calculate the average distance...Ch. 4 - Every time we alloy a metal, it gets stronger. Is...Ch. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75DPCh. 4 - You would like a metal plate with good...Ch. 4 - Prob. 4.77DPCh. 4 - Temperature dependence of vacancy conc enlralwns....Ch. 4 - Prob. 4.79CPCh. 4 - Prob. 4.80CPCh. 4 - Describe the problems associated with metal...Ch. 4 - Prob. 4.2KP
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- Consider 0.65 kg of N2 at 300 K, 1 bar contained in a rigid tank connected by a valve to another rigid tank holding 0.3 kg of CO2 at 300 K, 1 bar. The valve is opened and gases are allowed to mix, achieving an equilibrium state at 290 K. Determine: (a) the volume of each tank, in m³. (b) the final pressure, in bar. (c) the magnitude of the heat transfer to or from the gases during the process, in kJ. (d) the entropy change of each gas and of the overall system, in kJ/K.arrow_forwardBài 1. Cho cơ hệ như hình 1. Hình biểu diễn lược đổ cơ hệ tại vị trí cân bằng tĩnh. Trục tọa độ Oy hướng theo phương chuyển động của vật 1, gốc O đặt tại vị trí cân bằng của vật 1(tức khi lò xo biến dạng tĩnh). Bỏ qua khối lượng của thanh số 3. Vật rắn 2 là pulley 2 tầng đồng chất có bán kính ngoài 21, bán kính trong I, bán kính quán tính đối với trục qua tâm P-1.5, khối lượng m:. Vật rắn 4 là thanh thắng đồng chất có khối lượng m, chiều dài 1. Cho các số liệu: m = 2kg, m= = 5kg, m = 4kg, k=40(N/cm), ! – 0.8(m),r=0.1(m). Điều kiện đầu y; =0.5 cm );j = 10 cm/s) . Giả sử hệ dao động bé, Vật rắn 2 chuyển động lăn không trượt trên mặt phẳng ngang. 1. Viết phương trình chuyển động của hệ. 2. Xác định tần số dao động tự do của hệ. 3. Xác định đáp ứng dao động tự do của hệ. dây dây 1 2r Hình 1 y 3 -2 I k www. -2arrow_forwardHints: Find the closed loop transfer function and then plot the step response for diFerentvalues of K in MATLAB. Show step response plot for different values of K. Auto Controls Show solutions and provide matlab code NO COPIED ANSWERS OR WILL REPORTarrow_forward
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