The maximum number of balance equations that can be written for each of the subsystems given are to be stated and the order of these equations to be solved for the unknown variables is to be determined. Concept introduction: In a system, a conserved quantity (total mass, mass of a particular species, energy or momentum) is balanced and can be written as: input + generation − output − consumpumtion = accumulation Here, ‘input’ is the stream which enters the system. ‘generation’ is the term used for the quantity that is produced within the system. ‘output’ is the stream which leaves the system. ‘consumption’ is the term used for the quantity that is consumed within the system. ‘accumulation’ is used for the quantity which is builds up within the system. All the equations which are formed are then solved simultaneously to calculate the values of the unknown variables.

Question

Want to see the full answer?

Answer 1

Question

Chapter 4, Problem 4.38P

Interpretation Introduction

Interpretation:

The maximum number of balance equations that can be written for each of the subsystems given are to be stated and the order of these equations to be solved for the unknown variables is to be determined.

Concept introduction:

In a system, a conserved quantity (total mass, mass of a particular species, energy or momentum) is balanced and can be written as:

input+generation−output−consumpumtion=accumulation

Here, ‘input’ is the stream which enters the system. ‘generation’ is the term used for the quantity that is produced within the system. ‘output’ is the stream which leaves the system. ‘consumption’ is the term used for the quantity that is consumed within the system. ‘accumulation’ is used for the quantity which is builds up within the system.

All the equations which are formed are then solved simultaneously to calculate the values of the unknown variables.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A 0.45 mol/kg aqueous solution of 3-(methylamino)propylamine and 1-methylpiperazine (1:1 molar) flows at 0.5 g/s through a 2.5 m horizontal stainless steel coil (inner diameter 1.2 mm), entering at 358.15 K and 22 MPa and exiting at 20 MPa. A constant wall heat flux of 28 W is applied. Local density and isobaric heat capacity are obtained through from the Benedict–Webb–Rubin equation of state, with a 3% increase in heat capacity to account for wall sorption. Dynamic viscosity is obtained using the Green-Kubo relation with a given integral value of 2.1 × 10⁻¹⁰ Pa².s, and thermal conductivity is assumed constant. The local Nusselt number is corrected for thermal development using Nu(x) = 3.66 + (0.065 · Gz(x)^0.7) / (1 + 0.04 · Gz(x)^0.7), where Gz(x) = D · Re(x) · Pr(x) / x. Through a spatially resolved numerical integration of the 1D steady-state energy equation and determine the outlet temperature (K).

A pilot process is being planned to produce antibiotic P. Antibiotic P is a compound secreted by microorganism A during the stationary phase. To produce P, substrate S is required. The growth of microorganism A follows the Monod equation, with a maximum specific growth rate $\mu_m = 1 h^{-1}$ and a half-saturation constant $K_s = 700\ mg/L$.The pilot process uses a chemostat with a working volume of $1000\ L$. In this chemostat, the outflow is processed to separate microorganisms, which are then concentrated tenfold and recycled. A sterile medium containing $15\ g/L$ of substrate is supplied at a flow rate of $100\ L/h$, while the recycled flow (concentrated) contains $5\ g/L$ and is also fed into the chemostat.Microorganism A yields $0.5\ g$ of biomass per $1\ g$ of substrate consumed $(Y^M_{X/S} = 0.5\ g\ A/g\ S)$, and its death rate $(k_d)$ is negligible. Additionally, $1\ g$ of microorganism A produces $0.05\ g$ of antibiotic P per hour $(q_P = 0.05 g\ P/h\cdot g\ A)$, and $1\ g$…

In the production of ethyl acetate via reactive distillation, the column operates at 5 bar with an equimolar feed (ethanol + acetic acid) at 80°C. The reaction follows: \[CH_3COOH + C_2H_5OH \rightleftharpoons CH_3COOC_2H_5 + H_2O \quad (K_{eq} = 4.2 \text{ at } 80°C)\] Given: - NRTL parameters for all binary pairs - Tray efficiency = 65% - Vapor-liquid equilibrium exhibits positive azeotrope formation Calculate the exact minimum reflux ratio required to achieve 98% ethyl acetate purity in the distillate, assuming: 1) The reaction reaches equilibrium on each tray 2) The heavy key component is water