Chapter 4, Problem 4.34P

Interpretation Introduction

Interpretation:

To find the outlet temperature, T, of ammonia gas from the reactor.

Concept Introduction:

By definition of rate of change of enthalpy,

$\Delta H_R=R\times MCPH(T_0,T,A,B,C,D)\times (T-T_0)$

Where

$MCPH=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

${\displaystyle {\int }_{T_0}^T\frac{C_P}{R}}dT=A.T_0(\tau -1)+\frac{B}{2}{T}_0^2({\tau }^2-1)+\frac{C}{3}{T}_0^3({\tau }^3-1)+\frac{D}{T_0}(\frac{\tau -1}{\tau })=ICPH(T,T_0,A,B,C,D)$

A,B,C,D are constants

T₀ = Initial temperature

T = Final temperature

R = Universal Gas Constant = 8.314 J/mol K

$\tau =\frac{T}{T_O}$

$\Delta H=\Delta H_R+\Delta H_{298}+\Delta H_p=0$

$\Delta H_R$ = Change of enthalpy of Reactants stream

$\Delta H_{298}$ = Standard enthalpy at 298K

$\Delta H_P$ = Change of enthalpy of Products stream

$\Delta H$ = Total heat transferred