Chapter 4, Problem 4.28QP

(a)

Interpretation Introduction

Interpretation: The solubility of compounds are given in grams per $100\text{mL}$ of the solution. The compound that forms one molar solution is to be identified.

Concept introduction: The maximum molarity of the solution is calculated by the formula,

$\text{Molarity}=\frac{\text{Grams}\text{of}\text{solute}\times \text{1000}}{\text{Molar}\text{mass}\times \text{Volume}\text{of}\text{the}\text{solution}\text{in}\text{milliliters}}$

To determine: If ${\text{CuSO}}_{\text{4}}$ forms a one molar solution.

(b)

Interpretation Introduction

To determine: If $\text{Ba}{\left(\text{OH}\right)}_{\text{2}}$ forms a one molar solution.

(c)

Interpretation Introduction

To determine: If ${\text{FeCl}}_2$ forms a one molar solution.

(d)

Interpretation Introduction

To determine: If $\text{Ca}{\left(\text{OH}\right)}_{\text{2}}$ forms a one molar solution.