INQUIRY INTO PHYSICS-EBOOK
INQUIRY INTO PHYSICS-EBOOK
8th Edition
ISBN: 9780357540039
Author: Ostdiek
Publisher: CENGAGE L
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Chapter 4, Problem 41Q
To determine

The buoyant forces on the block from largest to smallest.

Expert Solution & Answer
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Answer to Problem 41Q

Thus, the buoyant forces will be arranged as

0.05>0.0375>0.03>0.02

(a)>(b)>(c)=(e)>(d).

Explanation of Solution

Given data:

  1. Mb = 0.04kg; Ml = 0.20kg.
  2. Mb = 0.03kg; Ml = 0.15kg.
  3. Mb = 0.04kg; Ml = 0.12kg.
  4. Mb = 0.02kg; Ml = 0.08kg.
  5. Mb = 0.03kg; Ml = 0.12kg.

Formula used:

The buoyant force is calculated by the following formula:

Fb=ρlVdg.

Calculation:

Having the known values, buoyant force is calculated as:

Fb=ρlVdg(a)   Mb=0.04kg; Ml=0.20kgρl=massof liquidvolume of liquid=0.20VlVd=voulume of blockVd=Vb=Vl4Fb=( 0.20 V l )( V l 4)g=0.204gFb=0.05kg(b)   Mb=0.03kg; Ml=0.15kgρl=0.15VlFb=( 0.15 V l )( V l 4)g=0.154gFb=0.0375kg

(c)   Mb=0.04kg; Ml=0.12kgρl=0.12VlFb=( 0.12 V l )( V l 4)g=0.124gFb=0.03kg

(d)   Mb=0.02kg; Ml=0.08kgρl=0.08VlFb=( 0.08 V l )( V l 4)g=0.084gFb=0.02kg

(e)   Mb=0.03kg; Ml=0.12kgρl=0.12VlFb=( 0.12 V l )( V l 4)g=0.124gFb=0.03kg.

Conclusion:

Thus, the buoyant forces will be arranged as:

0.05>0.0375>0.03>0.02

(a)>(b)>(c)=(e)>(d).

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Chapter 4 Solutions

INQUIRY INTO PHYSICS-EBOOK

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