Concept explainers
Define the following leveling terms:
- vertical control
- elevation, and
- vertical datum.
i.
Definition of vertical control.
Explanation of Solution
Vertical control, also known as basic control or level control is the series of points with known elevation or the benchmarks established on entire area.
The data sheets for vertical control give the
(1) Set of reference points for the station.
(2) Observed or modeled gravity reading at the station, and
(3) Description of the station, its location and juxtaposing details between the stations.
ii.
Definition of elevation.
Explanation of Solution
Elevation of a point is defined as the vertical distance that is measured along a vertical line with reference to some chosen vertical datum or object, it's also known as the height above the datum or orthometric height. If the elevation of any point is 450 ft, it means the point is 450 ft from the reference datum.
iii.
Definition of Vertical datum.
Explanation of Solution
Any equipotential or level surface is where the elevations are compared, thereby, calculating every other distance from this surface. This is the surface that is subjectively appointed to an elevation of value zero and is known as reference datum as the points utilizing this datum have heights practically identical to this surface. For example, if the elevation of any point is 450 ft, it means the point is 450 ft distant from the reference datum or vertical datum.
Want to see more full solutions like this?
Chapter 4 Solutions
Elementary Surveying (14th Edition)
Additional Engineering Textbook Solutions
Starting Out with Java: From Control Structures through Objects (7th Edition) (What's New in Computer Science)
Starting Out with C++ from Control Structures to Objects (9th Edition)
Introduction To Programming Using Visual Basic (11th Edition)
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Java: An Introduction to Problem Solving and Programming (8th Edition)
Java How to Program, Early Objects (11th Edition) (Deitel: How to Program)
- P.3.4 A mercury U-tube manometer is used to measure the pressure drop across an orifice in pipe. If the liquid that flowing through the orifice is brine of sp.gr. 1.26 and upstream pressure is 2 psig and the downstream pressure is (10 in Hg) vacuum, find the reading of manometer. Ans. R=394 mm Hgarrow_forwardProject management questionarrow_forwardQ5/B with Explantion plsarrow_forward
- project management question Q5/Barrow_forwardProblem 1: Given: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design. Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 Y=0.9 16 1.6 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 00 K₁ = P₁/f'c Ag 1.2 12 0.03 0.25 1.0 10 0.02 0.01 0.8 0.6 0.4 €,= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Agharrow_forwardGiven: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design.arrow_forward
- Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 P=0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 7=0.9 1.6 16 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 90 K₁ = P₁/f'Ag 1.2 0.03 0.25 0.02 1.0 0.01 0.8 0.6 0.4 €= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Aharrow_forwardGiven: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu=354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio () and ties. Sketch the design.arrow_forwardSee Figure (1) below. A 14 in. wide and 2 in. thick plate subject to tensile loading has staggered holes as shown. Compute An and Ae. P 2.00 3.00 4.00 3.00 2.00 ΕΙ T A B C F G D S = 2.50 3/4" bolts in 13/16" holes 14x12 PL Parrow_forward
- Architectural Drafting and Design (MindTap Course...Civil EngineeringISBN:9781285165738Author:Alan Jefferis, David A. Madsen, David P. MadsenPublisher:Cengage Learning