The slope of the provided equation line in words and the reason of considering zero.

Question

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Answer 1

Question

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

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Answer 2

Question

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

Answer 6

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

Answer 7

Chapter 4, Problem 4.1AYK

a.

To determine

To explain: The slope of the provided equation line in words and the reason of considering zero.

Answer 8

a.

Expert Solution

Explanation of Solution

Given:

The equation of the regression line is:

BAC=0.023×number of drinks

he general equation of the least squares line is:

y^=a+bx

Here, a represents the y-intercept and b represents the slope of the line.

By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the BAC=0.023×number of drinks is 0.023

A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .

The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.

Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is BAC=0.023×number of drinks .

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

Answer 13

b.

To determine

To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.

Answer 14

b.

Expert Solution

Explanation of Solution

Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:

BAC=0.038× number of drinks

Answer 15

b.

Expert Solution

Answer 16

b.

Expert Solution

Answer 17

Expert Solution

Answer 18

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body

Answer 19

c.

To determine

To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.

Answer 20

c.

Expert Solution

Explanation of Solution

The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:

BAC=0.023× number of drinks=0.023×4=0.092

Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:

BAC=0.038× number of drinks=0.038(2)=0.076

The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body