PRACTICE OF STATS - 1 TERM ACCESS CODE
4th Edition
ISBN: 9781319403348
Author: BALDI
Publisher: Macmillan Higher Education
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Question
Chapter 4, Problem 4.1AYK
a.
To determine
To explain: The slope of the provided equation line in words and the reason of considering zero.
a.
Expert Solution
Explanation of Solution
Given:
The equation of the regression line is:
he general equation of the least squares line is:
Here, a represents the y-intercept and b represents the slope of the line.
By comparing the general equation of the least-squares line with the provided equation of a least squares line, it can be said that the slope of the
A positive slope indicates that an average increase (or decrease) in the value of y for each unit increase (or decrease) in the value of x . A negative slope indicates that an average increase (or decrease) in the value of y for each unit decrease (or increase) in the value of x .
The provided least squares line has a slope of 0.023. So, the value of BAC increases by 0.023 for a unit increase in number of drinks.
Here, the provided least square line does not contain the intercept term. Thus, it could be said that the intercept term is
b.
To determine
To find: The equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman.
b.
Expert Solution
Explanation of Solution
Using the provided information, the equation of the regression line that could be used to predict BAC from number of drinks for a 120-pound woman could be written as:
c.
To determine
To find: The predicted BAC for a 160-pound male who consumed 4 drinks and for 120-pound women that consumed 2 drinks.
c.
Expert Solution
Explanation of Solution
The predicted BAC for a 160-pound male who consumed 4 drinks can be calculated as:
Now, the predicted BAC for 120-pound women who consumed 2 drinks can be calculated as:
The obtained values of BAC for male and female do not depict the actual blood alcohol content because there would be other factors that would affect the alcohol content in the body
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
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02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
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NORTH CAROLINA
ARKANSAS
WASHINGTON
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Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
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Chapter 4 Solutions
PRACTICE OF STATS - 1 TERM ACCESS CODE
Ch. 4 - Prob. 4.1AYKCh. 4 - Prob. 4.2AYKCh. 4 - Prob. 4.3AYKCh. 4 - Prob. 4.4AYKCh. 4 - Prob. 4.5AYKCh. 4 - Prob. 4.6AYKCh. 4 - Prob. 4.7AYKCh. 4 - Prob. 4.8AYKCh. 4 - Prob. 4.9AYKCh. 4 - Prob. 4.10AYK
Ch. 4 - Prob. 4.11AYKCh. 4 - Prob. 4.12AYKCh. 4 - Prob. 4.13AYKCh. 4 - Prob. 4.15CYSCh. 4 - Prob. 4.16CYSCh. 4 - Prob. 4.17CYSCh. 4 - Prob. 4.18CYSCh. 4 - Prob. 4.19CYSCh. 4 - Prob. 4.20CYSCh. 4 - Prob. 4.21CYSCh. 4 - Prob. 4.22CYSCh. 4 - Prob. 4.23CYSCh. 4 - Prob. 4.24CYSCh. 4 - Prob. 4.25ECh. 4 - Prob. 4.26ECh. 4 - Prob. 4.28ECh. 4 - Prob. 4.29ECh. 4 - Prob. 4.30ECh. 4 - Prob. 4.31ECh. 4 - Prob. 4.32ECh. 4 - Prob. 4.33ECh. 4 - Prob. 4.34ECh. 4 - Prob. 4.35ECh. 4 - Prob. 4.36ECh. 4 - Prob. 4.37ECh. 4 - Prob. 4.38ECh. 4 - Prob. 4.39ECh. 4 - Prob. 4.40ECh. 4 - Prob. 4.41ECh. 4 - Prob. 4.42E
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