The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined. Concept introduction: Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows: Mass percent of compound = ( mass of the compound mass of mixture )
The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined. Concept introduction: Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows: Mass percent of compound = ( mass of the compound mass of mixture )
The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined.
Concept introduction:
Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows:
Mass percent of compound=(mass of the compoundmass of mixture)
(b)
Interpretation Introduction
Interpretation:
The mass percentage of Mg in a magnesium-aluminium alloy that reacts with excess aqueous HCl and forms 1.38×10−2molH2 is to be determined.
Concept introduction:
Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.
Consider the general reaction,
A+2B→3C
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
(c)
Interpretation Introduction
Interpretation:
The mass percentage of Mg in a magnesium-aluminium alloy that reacts with excess O2 and forms 0.483g of oxide is to be determined.
Concept introduction:
Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.
Consider the general reaction,
A+2B→3C
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
Please do these questions within the SCH4U course please with full steps since I am still unsure how to format my answers! Thank you so much.
When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.