Construction Materials, Methods and Techniques (MindTap Course List)
4th Edition
ISBN: 9781305086272
Author: William P. Spence, Eva Kultermann
Publisher: Cengage Learning
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Chapter 4, Problem 3RQ
To determine
The various methods used in controlling site drainage
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Given an existing two-story steel structure with interior columns spaced as shown in Fig.2. The columns are spaced at 18 ft in the North-South direction and at 30 ft in the East-West direction. An interior lower-story column is to be removed by adding newsteel girder as shown in Fig. 4. The floor dead loads and the roof dead loads are 70 psfand 18 psf respectively. The floor live loads and the roof live loads are 50 psf and20 psf respectively. All existing steel materials are ASTM A36 steel (Fy=36 ksi). Newgirder is ASTM A992 steel (Fy= 50 ksi). All columns are W8x31. Use the LRFD Method.Assumptions:1- The loads given include column and beam self weights.2- Existing beam and new girder are simply supported at both ends.3- New girder top flange is laterally braced at mid span and at girder ends only.4- Columns are continuous from foundation to roof and are prevented from sway atfloor level and at roof level in both directions.5- Columns are pin supported at foundation, at floor level,…
Find
Determine the vertical reaction at A for the beam shown and a settlement of ½" at support B.
a. 45.6 k
b. 41.6 k
c. 42.7 k
d. 40.7 k
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Construction Materials, Methods and Techniques (MindTap Course List)
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- What are the states of stress (magnitude and tension/compression of the normal stresses and shear stress) at Point J and Point K?arrow_forwardConsider, M people (aka pax) who want to travel by car from O to D. They all start working at D at Q (e.g., Q-8am). If a person departs at time t, assume the time needed to go from O to D is given by c(t)=A+Bx(t), where x(t) is the flow of people departing at time t [car/unit of time]. In addition, a is the penalty for being early at work (E(t) is how early the person arrived when departing at time t), and ẞ is the penalty for being late at work (L(t) is how late the person arrived when departing at time t). Assume 0 < a < 1 < ß. Further assume the departure time choice problem under the equilibrium conditions. Prove that the arrival time of people who depart when most of the M people start their trips is equal to Q.arrow_forwarda. A b. A 3. Sketch normal depth, critical depth and the water surface profile. Assume at A and B the water is flowing at normal depth. Label and Identify all curves (i.e., M1, S2, etc.) Yn > Ye Уп Ye Уп> Ус yarrow_forward2. Design a trapezoidal ditch to carry Q = 1000 cfs. The ditch will be a lined channel, gravel bottom with sides shown below on a slope of S = 0.009. The side slopes of the 20-ft wide ditch will be 1 vertical to 3 horizontal. a) Determine the normal depth of flow (yn) using the Normal value for Manning's n. b) If freeboard requirements are 25% of the normal depth, how deep should the ditch be constructed? c) Classify the slope. T b Уп Z 1 Yn + FBarrow_forwardP15.45 WP A stainless steel pipe (Figure P15.45) with an outside diameter of 2.375 in. and a wall thickness of 0.109 in. is subjected to a bending moment M = 50 lb ft and an internal pressure of 180 psi. Determine the absolute maximum shear stress on the outer surface of the pipe. M FIGURE P15.45 Marrow_forward10.72 What power must the pump supply to the system to pump the oil from the lower reservoir to the upper reservoir at a rate of 0.3 m³/s? Sketch the HGL and the EGL for the system. p=940 kg/m³ v = 10-5 m²/s Elevation 100 m Elevation 112 m L= 150 m Oil Steel pipe D = 30 cm Problem 10.72arrow_forwardL / 83° 28° $75°E M 202° Q2: The scanning process was completed from point J to point N. The direction of the straight line was LM and the angles of deviation are shown in the figure below. Find the direction of the remaining sides? Narrow_forwardQ3: The scanning process was completed from point F to point G. The direction of the line Fl and the angles of deviation and interior are shown in the figure below. Find the direction of the remaining sides? Azimn = 60° F 52° 52° 72° R= 572.958/D ° T-R tan(A/2) • LC 2R sin (A/2) • E-R (sec(A/2)-1) • M-R (1-cos (A/2)) L= 10 A/D •C=2R sin(2D/2) • d=Dc/10 c' 2R sin (d/2) • Y= √√R2-X2-K • K= R2- K=R-M G H معادلات :مفيدةarrow_forwardPlease write me Background Reviews;arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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